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lord [1]
3 years ago
9

WILL MARK BRAINLIEST!!!

Physics
1 answer:
sashaice [31]3 years ago
5 0

Answer:

OHHH.. I know what you talking about.

Explanation:

Okay so Netforce escape room is a Game on the playstore app and every time you type the code in it unlocks the door and you move up to different levels.

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A parallel-plate capacitor made of circular plates of radius 75 cm separated by 0.15 cm is charged to a potential difference of
ElenaW [278]

Answer:

See the attached pictures for detailed steps.

Explanation:

5 0
3 years ago
A steel wire of length 31.0 m and a copper wire of length 17.0 m, both with 1.00-mm diameters, are connected end to end and stre
Brut [27]

Answer:

The time taken is  t =  0.356 \ s

Explanation:

From the question we are told that

  The length of steel the wire is  l_1  = 31.0 \ m

   The  length of the  copper wire is  l_2  = 17.0 \ m

    The  diameter of the wire is  d =  1.00 \ m  =  1.0 *10^{-3} \ m

     The  tension is  T  =  122 \ N

     

The time taken by the transverse wave to travel the length of the two wire is mathematically represented as

              t  =  t_s  +  t_c

Where  t_s is the time taken to transverse the steel wire which is mathematically represented as

         t_s  = l_1 *  [ \sqrt{ \frac{\rho * \pi *  d^2 }{ 4 *  T} } ]

here  \rho_s is the density of steel with a value  \rho_s  =  8920 \ kg/m^3

   So

      t_s  = 31 *  [ \sqrt{ \frac{8920 * 3.142*  (1*10^{-3})^2 }{ 4 *  122} } ]

      t_s  = 0.235 \ s

 And

        t_c is the time taken to transverse the copper wire which is mathematically represented as

      t_c  = l_2 *  [ \sqrt{ \frac{\rho_c * \pi *  d^2 }{ 4 *  T} } ]

here  \rho_c is the density of steel with a value  \rho_s  =  7860 \ kg/m^3

 So

      t_c  = 17 *  [ \sqrt{ \frac{7860 * 3.142*  (1*10^{-3})^2 }{ 4 *  122} } ]

      t_c  =0.121

So  

   t  = t_c  + t_s

    t =  0.121 + 0.235

    t =  0.356 \ s

4 0
3 years ago
The ___________ effect is the change of pitch heard when the source of the sound approaches and then moves away from a stationar
mina [271]
The answer is the Doppler Effect
6 0
4 years ago
Read 2 more answers
imagine that you are on a spaceship that is far from the sun or any planet. Explain why a 500 kg piece of equipment would be dif
Mila [183]

Even though the object is weightless, it would need inertia, I.e, you pushing it or any form of transportation. So you would still have to push that 500kg to just keep it moving in space. Say if it were a planet with less gravitational force, it would be weightless.

8 0
3 years ago
True or false: Only people that hold opinions of the group should get to express their opinion.
PilotLPTM [1.2K]

Answer:

true

Explanation:

this is fair to other people

5 0
3 years ago
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