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Morgarella [4.7K]
2 years ago
8

Why is quantum computing potentially a better fit for weather forecasting than classical computers?.

Physics
1 answer:
Firdavs [7]2 years ago
7 0

Quantum computing is a better fit than classical computing because it can access advanced simulations for vast quantities of weather.

What is Quantum computing?

Quantum computing can process large number of data sets of weather for all the properties of quantum states. Unlike classical computers which contains only standard bits 0 and 1 , quantum computing use Qubit or Quantum bit in which there are more than two standard sets of bits. These Qubits can measure the light at any degrees of polarisation between 1 and 0.This is the spin attribute that corresponds to superposition. This can create a lot more possibilities beacuse we can run multiple tasks at once with only one bit of data beacuse of the superpositioned qubit. This unlike classical computers where the bit can be only 1 and 0 is more effectively used in breaking encryption tasks.

So, the analysis of vast quantities of weather data can be done in seconds using Quantum computing.

Learn more about Quantum computing here:

brainly.com/question/15188300

#SPJ1

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A 1.70-μF capacitor is charging through a 14.0-Ω resistor using a 10.0- V battery. What will be current when the capacitor has a
RoseWind [281]

Answer:

The current is 0.951 A

Solution:

As per the question:

Capacitance of the capacitor, C = 1.70\mu F

Resistance of the circuit, R = 14.0\Omega

Voltage of the battery, V = 10.0 V

Now, when the charge become one-fourth of its initial value, the amount of current flowing is given by:

q' = q(1 - e^{-\frac{t}{\tau}})          (1)

where

q' = \frac{q}{4}

\tau = RC

q' = q(1 - e^{-\frac{t}{RC}})

\frac{q}{4} = q(1 - e^{-\frac{t}{RC}})

0.25 = (1 - e^{-\frac{t}{RC}})

0.75 = e^{-\frac{t}{RC}

-\frac{t}{RC} = ln(0.75)

-\frac{t}{14\times 1.70\times 10^{- 6}} = - 0.2876

t = 6.844\times 10^{- 6} s

Now,

The current is given by:

I' = Ie^{-\frac{t}{RC}}                  (2)

Also, I = \frac{V}{R} = \frac{10}{14} = 0.714 A

Now, using the value of I = 0.714 A

I' = 0.714e^{-\frac{6.844\times 10^{- 6}}{14\times 1.70\times 10^{- 6}}} = 0.951 A

3 0
3 years ago
Read 2 more answers
Area is found by multiplying the length of a surface times the width. If a floor measures 5.28 m2, how many square centimeters d
Scilla [17]
62,500 cm^2.........
8 0
3 years ago
A small 21 kilogram canoe is floating downriver at a speed of 1 m/s. What is the canoe's kinetic energy?
tamaranim1 [39]
Kinetic energy is the energy of a moving object.
Kinetic energy can be calculated using the following equation;
K.E = \frac{1}{2} m v^{2}
where - m - mass of object
v - speed of object 
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K.E = 1/2 x 21 kg x (1 m/s)²
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8 0
4 years ago
A tree loses water to the air by the process of transpiration at the rate of 110 g/h. This water is replaced by the upward flow
Vinvika [58]

Answer:

The answer is 1.87nm/s.

Explanation:

The 110g/hr  water loss must be replaced by 110g/hr of sap. 110g of sap corresponds to a volume of  

110g \div \dfrac{1040*10^3g}{1*10^6cm^3}  = 106cm^3

thus rate of sap replacement is

106cm^3/hr = 106*10^{-6}m^3/3600s  = 2.94*10^{-8}m^3/s

The volume of sap in the vessel of length x is

V = Ax,

where A is the cross sectional area of the vessel.

For 2000 such vessels, the volume is

V = 2000Ax

taking the derivative of both sides we get:

\dfrac{dV}{dt} = 2000A \dfrac{dx}{dt}

on the left-hand-side \dfrac{dx}{dt} is the velocity v of the sap, and on right-hand-side \dfrac{dV}{dt}  = 2.94*10^{-8}m^3/s; therefore,

2.94*10^{-8}m^3/s=2000Av

and since the cross-sectional area is

A = \pi (\dfrac{100*10^{-3}m}{2} )^2 = 7.85*10^{-3}m^2;

therefore,

2.94*10^{-8}m^3/s =2000(7.85*10^{-3}m^2)v

solving for v we get:

v = \dfrac{2.94*10^{-8}m^3/s}{2000(7.85*10^{-3}m^2)}

\boxed{v =1.875*10^{-9}m/s = 1.875nm/s}

which is the upward speed of the sap in each vessel.

4 0
4 years ago
What are two processes that result in rocks being broken down into smaller pieces ?
meriva
Mechanical and Chemical. (Weathering and erosion)
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4 years ago
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