Answer:
Knowing we only have one load applied in just one direction we have to use the Hooke's law for one dimension
ex = бx/E
бx = Fx/A = Fx/π
Using both equation and solving for the modulus of elasticity E
E = бx/ex = Fx / πex
E = 
Apply the Hooke's law for either y or z direction (circle will change in every direction) we can find the change in radius
ey = 
(бy - v (бx + бz)) = 
бx
= 
= 
Finally
ey = Δr / r
Δr = ey * r = 10 * 
Δd = 2Δr = 
Explanation:
Answer:
400.7886829 rad/s
Explanation:
First we have to turn our 0.35 rev/s into rad/s using the equation
(Xrev/s)*2pi=Xrad/s we can plug in .35*2pi=.7pi rad/s
Now we can us the equation m_1*v_1*r_1^2=m_1*v_2*r_2^2 we can plug in the given. Because the mass remains the same we can cross it off of both sides giving us just: v_1*r_1^2=v_2*r_2^2
(.7pi)*(.54)^2=(v_2)*(.04)^2
(.20412pi)=(v_2)*(.0016) [.20412pi=.6412618925]
then using division on both sides we get
(.6412618925/.0016)=v_2=400.79rad/s(This answer is rounded to the nearest hundreth)
See you in Mr.K's class tomorrow! -Ruben
Answer:
Balanced forces.
Explanation:
The three main forces that stop moving objects are friction, gravity and wind resistance. Equal forces acting in opposite directions are called balanced forces. Balanced forces acting on an object will not change the object's motion. When you add equal forces in opposite direction, the net force is zero.
