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zloy xaker [14]
3 years ago
13

Changing the pressure of a system has the highest effect on a substance in which phase?

Chemistry
1 answer:
katrin2010 [14]3 years ago
7 0
The answer is A- Gas.
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Ostrovityanka [42]
Two
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3 years ago
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How many moles are in 117.30 grams of KCLO3?
eduard

0.0081599680129254

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5 0
2 years ago
BRAINLIESTTT ASAP!! PLEASE HELP ME :)
AlladinOne [14]

Answer : False, there will be two lithium and one oxygen atoms in a unit molecular structure of lithium oxide.

Explanation:

Electronic configuration of lithium is :

Li=1s^2s^1

In order to attain stable electronic configuration it will loose an electron and form positively charge cation.

Li^+=1s^22s^0

The electronic configuration of oxygen is:

O=1s^22s^22p^4

Oxygen being second most electronegative atom requires two electrons to attain noble gas configuration stability and form negatively charge ion with 2- charge.:

O^{2-}=1s^22s^22p^6

When two atom of lithium and oxygen comes together , one electron from each lithium atom get transferred to an oxygen atom which results in formation of lithium oxide.

2Li^++O^{2-}\rightarrow Li_2O

4 0
3 years ago
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Enter the net ionic equation representing aqueous acetic acid neutralized by aqueous barium hydroxide.
IrinaK [193]

Answer:

The answer to your question is below

Explanation:

Data

Aqueous acetic acid

Aqueous barium hydroxide

Formula

Acetic acid    CH₃CH₂COOH

Barium hydroxide   Ba(OH)₂

Neutralization reaction

        CH₃CH₂COOH    +    Ba(OH)₂      ⇒  Ba( CH₃CH₂COO)₂ + H₂O

                                                                    Barium acetate + H₂O

Barium acetate =  Ba( CH₃CH₂COO)₂ = Ba(C₃H₅O₂)₂

6 0
3 years ago
what volume of N2 is required to convert 5.0L of hydrogen gas to ammonia? assume that all gases are at the same temperature and
____ [38]

Answer:

Approximately 1.7\; {\rm L}.

Explanation:

Nitrogen {\rm N_{2}}\, (g) reacts with hydrogen {\rm H_{2}}\, (g) at a 1:3 ratio to produce ammonia {\rm NH_3}\, (g):

{\rm N_{2}}\, (g) + 3\; {\rm H_{2}}\, (g) \to 2\; {\rm NH_{3}}\, (g).

The ratio between the coefficient of {\rm N_{2}}\, (g) and the coefficient of {\rm H_{2}}\, (g) is:

\begin{aligned}\frac{n({\rm N_{2}})}{n({\rm H_{2}})} = \frac{1}{3}\end{aligned}.

Under the ideal gas assumptions, the same ratio would apply to the volume of {\rm N_{2}}\, (g) and {\rm H_{2}}\, (g) in this reaction:

\begin{aligned}\frac{V({\rm N_{2}})}{V({\rm H_{2}})} = \frac{n({\rm N_{2}})}{n({\rm H_{2}})} = \frac{1}{3}\end{aligned}.

\begin{aligned}V({\rm N_{2}})= \frac{1}{3}\, V({\rm H_{2}})\end{aligned}.

Given that V({\rm H_{2}}) = 5.0\; {\rm L}:

\begin{aligned}V({\rm N_{2}}) &= \frac{1}{3}\, V({\rm H_{2}}) \\ &= \frac{1}{3}\times 5.0\; {\rm L} \\ &\approx 1.7\; {\rm L}\end{aligned}.

(Rounded to 2 significant figures.)

5 0
2 years ago
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