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2 years ago

Work and Power Practice Calculations

Physics

1 answer:

Elza [17]2 years ago

5 0

Answer:

1. W = F d = 20 N * 6 m = 120 J

2. F = W / d = 60 J / 2 m = 30 N

3. d = W / F = 350 J / 85 N = 4.12 m

4. P = W / t = F d / t = 45 N * 9 m / 10 s = 40.5 Watts

5. W = P t = 500 W * 120 sec = 60,000 J

6. t = W / P = 550 J / 310 W = 1.77 sec

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12.0-kg block is pushed across a rough horizontal surface by a force that is angled 30.0◦below thehorizontal. The magnitude of t

drek231 [11]

Answer: Fr = 26.53 N

Explanation: The constant force exerted on the block by the surface is the frictional force.

This frictional force is as a result of interaction between the body and the surface.

According to newton's second law of motion,

F - Fr = ma

F=applied force

Fr = magnitude of frictional force

m = mass of object = 12kg

a = acceleration of object = 3.2m/s²

The applied force (F= 75 N) is inclined at an angle of 30° to the horizontal thus making it have 2 components of forces given below

Fx = 75 * cos 30 = 64.95 N (horizontal component)

Fy = 75 * sin 30 = 37.5 N ( vertical motion)

The body moves across the surface, hence the horizontal component of force is responsible for motion.

F = 64.95 N

By substituting the parameters, we have that

64.96 - Fr = 12 * 3.2

64.96 - Fr = 38.4

Fr = 64.96 - 38.4

Fr = 26.53 N

7 0

3 years ago

Read 2 more answers

What is the frequency of a sound wave traveling at 335 m/s with a wavelength of .55 m?

irga5000 [103]

Answer:

v=f* lamba

f=v/lamba

f= 335/55

f=6.45 hertz

8 0

3 years ago

Different forces were applied to five balls, and each force was applied for the same amount of time. The data is in the table. A

Annette [7]

The magnitude of impulse on Ball A will become twice (doubles). Hence, option (c) is correct.

Impulse:

The effect of applied force acting for a very small interval of time is known as Impulse.

Given data:

The initial magnitude of the force on Ball A is, F = 50 N.

The time interval for the applied force on Ball A is, t = 1.25 s.

And the impulse at initial on ball A is, I = 62.5 N-s.

Now, if force on ball A doubles, which means new magnitude of force is,

F' = 2F

F' = 2 × 50

F' = 100 N

For same time interval, the new impulse on Ball A is given as,

I' = F' × t

Solving as,

I' = 100 × 1.25

I' = 125 N-s

Taking the ratio of both the impulses as,

I' / I = 125/62.5

I' = 2 I

Thus, we can conclude that the magnitude of impulse on Ball A will become twice (doubles). Hence, option (c) is correct.

Learn more about the impulse here:

brainly.com/question/904448

7 0

3 years ago

a diver on a board 7.5m above the water walks off the end with a horizontal velocity of 2.3 m/s when they hit the surface of the

m_a_m_a [10]

Answer:

2.846m

Explanation:

The diver is performing projectile motion.

To find x(final), we are going to use the equation x(final) = v(initial)*t + x(initial)

x(initial) = 0

x(final) = ?

v(initial) = 2.3 m/s

we don't know t

To find t we will use y(final) = 1/2*(-9.8)*t^2 + v(initial in the y dir.)*t + y(initial)

- 9.8 in the acceleration in the y dir.

y(final) = 0

y(initial) = 7.5

v(initial in the y dir.) = 0

If we solve for t we get: t = 1.237s

Now we have all the components to solve for x(final) in x(final) = v(initial)*t + x(initial)

x(final) = 2.3*1.237 + 0

x(final) = 2.846m

6 0

3 years ago

Un bloque de 750 kg es empujado hacia arriba por una pista inclinada 15º respecto de la horizontal. El coeficiente de rozamiento

kotegsom [21]

Answer:

4776.98 N is the minimum force to start the rise.

Explanation:

We can use the first Newton's law to find the minimum force to move the block.

So we will have:

$F-W_{x}-F_{f}=0$

Where:

F is the force
W(x) is the weight of the block in the x direction, W = mg*sin(15)
F(f) is the static friction force (F(f) = μN), μ is the static friction coefficient 0.4.

$F=W_{x}+F_{f}=mgsin(15)+\mu N$

$F=mgsin(15)+\mu mgcos(15)$

$F=mg(sin(15)+\mu cos(15))$

$F=750*9.81(sin(15)+0.4*cos(15))$

$F=4776.98 N$

Therefore 4776.98 N is the minimum force to move the block.

I hope it helps you!

8 0

3 years ago