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Law Incorporation [45]
2 years ago
5

A rectangle has an area measuring 1350 square centimeters. Its length and width are whole numbers of centimeters. What are the p

ossible combinations of length and width? which possibility gives the smallest perimeter?.
Physics
1 answer:
Aleks04 [339]2 years ago
7 0

The smallest perimeter of the rectangle is of value 150 cm.

Given:

The area of the rectangle, A = 1350 cm²

Calculation:

Let the length of the rectangle be 'x'

      the breadth of the rectangle be 'y'

We know that the area of a rectangle is given as:

A = (x) × (y)  

Applying values in the above equation we get:

xy = 1350 cm²

Factorizing the value of 1350, the possible values of length and breadth of the rectangle is as listed below:

x (cm)         y (cm)

1350      ×       1

675       ×       2

450       ×       3

270       ×       5

225       ×       6

150        ×       9

135        ×       10

90         ×       15

75         ×        18

54         ×        25

50         ×        27

45         ×        30         (least possible value)

Thus, the smallest perimeter of the rectangle can be calculated as:

P = 2 (x + y)

  = 2 (45 + 30)

  = 150 cm

Therefore, the smallest perimeter that the rectangle will have is 150 cm.

Learn more about factorization here:

<u>brainly.com/question/9231261</u>

#SPJ4

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Answer:

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