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Nat2105 [25]
2 years ago
9

What is the Difference between accuracy and precision ?​

Physics
2 answers:
levacccp [35]2 years ago
7 0

Accuracy means the state of being accurate, without any mistakes and the results should be 100% true.

Whereas, precision means, approximately true or almost true.

Hope it help you

Pie2 years ago
6 0

Answer:

Accuracy measures how close results are to the true or known value. Precision, on the other hand, measures how close results are to one another.

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A whale comes to the surface to breathe and then dives at an angle 24 degrees to the horizontal surface of the water. The whale
WARRIOR [948]

Given that,

A whale dives at an angle of 24 degrees to the horizontal surface of the water.

The whale continues in a straight line 145 m.

To find,

The horizontal and vertical components of the displacement of the whale.

Solution,

The horizontal component of displacement is :

d_x=d\cos\theta\\\\=145\times \cos(24)\\\\=132.46\ m

The vertical component of displacement is :

d_y=d\sin\theta\\\\=145\times \sin(24)\\\\=58.97\ m

<h3>Hence, the horizontal and vertical components of the displacement of the whale are 132.46 m and 58.97 m.</h3>
7 0
2 years ago
I’m stuck in B and D. which one is it?
tatuchka [14]
It is b! the lithosphere is the crust and upper mantle
6 0
3 years ago
Read 2 more answers
PLEASE HELP
bixtya [17]

Answer:

AS- X 3.42 Y 3. B) X Y c) x Ross TET V V. a 1.71 1.71 LLL LLL 2.42 N al

Explanation:

3 0
2 years ago
Read 2 more answers
A long cylindrical capacitor is made of a central wire of radius a = 2.50 mm surrounded by a conducting shell of radius b = 7.50
asambeis [7]

Answer:

The capacitance per unit length is 5.06\times10^{-11}\ F/m

(b) is correct option.

Explanation:

Given that,

Radius a= 2.50 mm

Radius b=7.50 mm

Dielectric constant = 3.68

Potential difference = 120 V

We need to calculate charge per length for the capacitance

Using formula of charge per length

\lambda=\dfrac{4\pi\epsilon_{0}\Delta V}{2 ln(\dfrac{r_{2}}{r_{1}})}

Put the value into the formula

\lambda=\dfrac{120}{9\times10^{9}\times2 ln(\dfrac{7.50\times10^{-3}}{2.50\times10^{-3}})}

\lambda=6.068\times10^{-9}\ C/m

We know that,

\lambda=\dfrac{Q}{L}

We need to calculate the capacitance per unit length

Using formula of capacitance per unit length

C=\dfrac{\dfrac{Q}{L}}{\Delta V}

C=\dfrac{6.068\times10^{-9}}{120}

C=5.06\times10^{-11}\ F/m

Hence, The capacitance per unit length is 5.06\times10^{-11}\ F/m

7 0
3 years ago
Objects are lighter on the moon than they are on earth. if an object A weighs 25lbs on the Moon and another object B weighs 25 N
solong [7]

Answer:

a. Object A

Explanation:

The mass of an object implies the quantity of matter in it, while the weight is the amount of gravitational force applied on an object.

The object A has a mass of 25 lbs, but object B on the earth has a weight, W, of 25 N.

So that,

For object A on the moon, mass = 25 lbs

For object B on the earth, W = 25 N,

W = m x g

25 = m x 10                (g = 10 m/s^{2})

m = \frac{25}{10}

   = 2.5 lbs

Mass of object B is 2.5 lbs.

Therefore, the mass of the object A is more than that of B.

5 0
2 years ago
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