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kirill115 [55]
3 years ago
10

How high can a 40 N force move a load, when 395 J of work is done?

Physics
1 answer:
Juliette [100K]3 years ago
7 0

Answer:

9.875

Explanation:

w=f×s

395=40×s

make s the subject of the formula

s=395/40

=9.875

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Answer:

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Explanation:

Given that,

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Using formula of angle

\tan\theta=\dfrac{8}{3}

\thta=\tan^{-1}\dfrac{8}{3}

\theta=69.44^{\circ}

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4 0
4 years ago
Read 2 more answers
A small object with a 5.0-mC charge is accelerating horizontally on a friction-free surface at 0.0050 m/s2 due only to an electr
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Answer:

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The electric field has a magnitude of 0.002 N/C.

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3 years ago
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