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kirill115 [55]
3 years ago
10

How high can a 40 N force move a load, when 395 J of work is done?

Physics
1 answer:
Juliette [100K]3 years ago
7 0

Answer:

9.875

Explanation:

w=f×s

395=40×s

make s the subject of the formula

s=395/40

=9.875

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Do you divide mass by volume to get density
bogdanovich [222]
Density<span> is the </span>mass<span> of an object </span>divided<span> by its </span>volume<span>. So the answer would be Yes. Hope it helps! (:</span>
7 0
3 years ago
1. Describe how the velocity
const2013 [10]

Velocity means DIRECTION and speed.

and if it's going down that's a different direction from up obviously.

6 0
3 years ago
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How much force is required to hold an empty carton of volume 1.5 L beneath the surface in a sink of water? Assume the carton is
Gwar [14]

Answer:

It will require 14.715 N of force to hold the cartoon beneath the water.

Explanation:

Given the the volume of cartoon is 1.5 liters.

We need to find the force required to hold this cartoon beneath the water.

As we know from the Archimedes principle that the net force is equal to the volume of liquid displaced.

Given volume of the cartoon is 1.5 liters. So, 1.5 liters of water will be displaced.

And we know the density of the water is 1000\ kg/m^3. That is 1\ kg/L

And g=9.81\ m/s^2

F_N=\rho Vg\\F_N=1\times 1.5\times 9.81\\F_N=14.715\ N

So, it will require 14.715 N of force to hold 1.5 liter volume of cartoon beneath the water.

6 0
3 years ago
A 4.88 x 10-6 C charge moves 265 m/s
Alex73 [517]

Answer:

F=0N

Explanation:

From the question we are told that:

Charge Q=4.88 x 10-6 C

Velocity v= 265m/s

Angle \theta =0 \textdegree

Magnetic field B=0.0579T

Generally the equation for Force is mathematically given by

 F=Q(\=v*\=B)

 F=qvBsin\theta

Therefore

 F=qvBsin0 \textdegree

 F=0N

5 0
3 years ago
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A brand new corvette can go from 0 to 85 miles per hour in 4.8 seconds.
klasskru [66]

Answer:

(A) 7.9 m/s^{2}  

(B) 19 m/s

(C) 91 m

Explanation:

initial velocity (U) = 0 mph = 0 m/s

final velocity (V) = 85 mph = 85 x 0.447 = 38 m/s

initial time (ti) = 0 s

final time (t) = 4.8 s

(A) acceleration = \frac{V-U}{t}

         = \frac{38-0}{4.8} = 7.9 m/s^{2}  

(B) average velocity = \frac{V+U}{2}

     =\frac{38+0}{2} = 19 m/s

(C) distance travelled (S) = ut + 0.5at^{2}

  =  (0 x 4.8) + 0.5 x 7.9 x 4.8^{2} = 91 m

5 0
3 years ago
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