Recall that average velocity <em>v</em> is given by
<em>v</em> = ∆<em>x</em>/∆<em>t</em>
where ∆<em>x</em> is displacement and ∆<em>t</em> is time.
Under constant acceleration, average velocity is also equal to the average of the initial and final velocities,
<em>v</em> = (<em>v</em>₂ + <em>v</em>₁)/2
The player starts at rest, so <em>v</em>₁ = 0, and speeds up to <em>v</em>₂ = 5.45 m/s in a matter of ∆<em>t</em> = 3.02 s. So
∆<em>x</em> = (<em>v</em>₂ + <em>v</em>₁) ∆<em>t</em> / 2
∆<em>x</em> = (5.45 m/s) * (3.02 s) / 2
∆<em>x</em> ≈ 8.23 m
Answer:
Explanation:
3. The word circuit means "go around", therefore a circuit is a pathway or closed path around which electricity (or water) flows.
4. Electrons flowing through a wire can be compared to water flowing through a hose. Once the flow of electrons or water is going, work, is performed.
5. You would get shocked in a bumper car by touching the floor and the ceiling at the same time. This means you are completing the circuit allowing electricity to flow.
6. Electricity from a wall outlet has enough energy to stop your
heart.
7. Electricity is the flow of electrons, because electrons move or jump from atom to atom.
8. Materials that allow electrons to move easily from atom to atom are called conductors.
9. Materials that do not allow electrons to flow easily are called insulators.
10. Semi- conductors are materials that are somewhere in between
.
11. Voltage is the force or pressure of electricity and is compared to the amount of water pressure in a hose.
12. Current (amps
) is the amount of electricity and is compared to the amount of water in a hose
.
13. Watts (power) is the term for work performed by electricity.
On the whole, the metals burn in oxygen to form a simple metal oxide. Beryllium is reluctant to burn unless it is in the form of dust or powder. Beryllium has a very strong (but very thin) layer of beryllium oxide on its surface, and this prevents any new oxygen getting at the underlying beryllium to react with it.
Answer:
66.4 m
Explanation:
To solve the problem, we can use the length contraction formula, which states that the length observed in the reference frame moving with the object (the rocket) is given by
where
is the proper length (the length measured from an observer at rest)
v is the speed of the object (the rocket)
c is the speed of light
Here we know
v = 0.85c
L = 35.0 m
So we can re-arrange the equation to find the length of the rocket at rest:
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