Answer:
Option D.
Explanation:
Methods of charging:
1. By friction: when two materials of different electro-negativities rub against each, electrons transfer from one material to another.
2. By induction: When a charged body is brought near an uncharged body, the later gets polarized.
3. By conduction: when electrons from one body to another uncharged while contact, it is known as charging by conduction.
Here, a flower is analogous to an electron. A box of candy is positive charge. A bouquet of flowers is like a charged body which is brought near an uncharged body. It induces charge on ti it by causing it to transfer electron to another.
Thus, option D is correct.
Answer:
a. inlet velocity = 60.8m/s
b. exit temperature = 686k
Explanation:
Answer:
<h3>The answer is 4 N</h3>
Explanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 2 × 2
We have the final answer as
<h3>4 N</h3>
Hope this helps you
Answer:
The correct option is
(e)either (c) or (d) could be correct.
Explanation:
The electric field of a charge radiates out in all directions and the intensity of the electric field strength given by E = F/q₀, diminishes as the lines of force moves further away from the source. The direction of F and E is in the line of potential motion of the source charge in the field.
Equipotential surfaces are locations in the radiated electric that have the same field strength or electric potential. The work done in moving within an equipotential surface is zero and as such since
Work = Force × distance = 0 where distance ≠ 0.
The force acting between two points on an equipotential surface is also zero or the component of the force within an equipotential surface is zero and since there is a force in the electric field, it is acting at right angles to the equipotential surface which could be horizontally to the left or right directions where the equipotential surfaces due to the charge distribution are in the vertical plane.
Therefore it is either horizontally to the left, or horizontally to the right.
Answer:
Part a)

Part b)
East of South
Explanation:
Part a)
Velocity of Juan is given as

velocity of the ball is given as

now we have

Part a)
We need to find velocity of ball with respect to Juan
so it is given as



magnitude of the speed is given as


Part b)
direction of velocity of the ball


East of South