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True [87]
3 years ago
11

A roller coaster car rapidly picks up speed as it rolls down a slope as it starts down the slope its speed is 4m/s but 3 seconds

later at the bottom of the slope its speed is 22m/s what is its average acceleration
Physics
1 answer:
Gwar [14]3 years ago
3 0

Answer:

The acceleration is 6 [m/s^2]

Explanation:

We can find the acceleration of the roller coaster using the kinematic equation for uniformly accelerated motion.

v_{f} =v_{i} + a*t\\where:\\v_{f} = final velocity = 22 [m/s]\\v_{i} = initial velocity = 4 [m/s]\\t = time = 3 [s]\\

Now replacing the values we have:

a=\frac{v_{f} - v_{i} }{t} \\a=\frac{22 - 4 }{3}\\a = 6 [m/s^{2} ]

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It is A) Charleston because it is the closest city to warm Atlantic waters.

6 0
4 years ago
A box of mass 20kg is pulled up an inclined plane by a force of 285N. Given that the value of the incline angle is 30 degrees an
docker41 [41]

Given :

Mass of box , m = 250 kg.

Force applied , F = 285 N.

The value of the incline angle is 30°.

the coefficient of dynamic friction is \mu=0.72 .

To Find :

The speed with which the box is moving with, assuming it takes 4 seconds to reach the top of the incline.

Solution :

Net force applied in box is :

F=285 - mgsin\ \theta - \mu mg cos \ \theta\\ \\F=285-mg( sin \ \theta - \mu cos\ \theta)\\\\F=285 - 20\times 10( \dfrac{1}{2}+0.72\times \dfrac{\sqrt{3}}{2})\\\\F=60.29\ N

Acceleration , a=\dfrac{F}{m}=\dfrac{60.29}{20}=3.01\ m/s^2.

By equation of motion :

v=u+at\\\\v=0+3.01\times 4\\\\v=12.04\ m/s

Therefore, the speed of box is 12.04 m/s.

Hence, this is the required solution.  

6 0
3 years ago
I need help/this is a major grade
Debora [2.8K]

Answer:

1e , 2j , 3c , 4d , 5k , 6a , 7i , 8b , 9m , 10h ,11g , 12f , 13l .

8 0
3 years ago
T Or F- True or False There three types of cloud's are .
AURORKA [14]

Answer:

There are three main cloud types.

The foundation consists of 10 major cloud types. In addition to cirrus, stratus, cumulus, and nimbus clouds, there are cirrostratus, cirrocumulus, altostratus, altocumulus, stratocumulus, nimbostratus, and cumulonimbus clouds. The following table places these cloud types into the four major cloud groups.

Explanation:

So false, depends what you have learned and your grade level ig

7 0
3 years ago
On planet X, the absolute pressure at a depth of 2.00 m below the surface of a liquid nitrogen lake is 5.00 × 105 N/m2 . At a de
eimsori [14]

Answer:

300000.01008 Pa

123.76237 m/s²

Explanation:

\rho = Density of liquid nitrogen = 808 kg/m³

h = Depth

g = Acceleration due to gravity

P = Atmospheric pressure

Absolute Pressure is given by

Below 2 m from surface

P_a=P+\rho gh\\\Rightarrow 5\times 10^5=P+808g\times 2

Below 5 m from surface

P_a=P+\rho gh\\\Rightarrow 8\times 10^5=P+808g\times 5

Subtracting the above equations we get

-3\times 10^5=-808g3\\\Rightarrow g=\frac{3\times 10^5}{808\times 3}\\\Rightarrow g=123.76237\ m/s^2

The acceleration due to gravity on the planet is 123.76237 m/s²

Equating the value of g in the first equation

5\times 10^5=P+808\times 123.76237\times 2\\\Rightarrow P=5\times 10^5-808\times 123.76237\times 2\\\Rightarrow P=300000.01008\ Pa

The atmospheric pressure on the planet is 300000.01008 Pa

7 0
4 years ago
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