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77julia77 [94]
2 years ago
10

In order to determine an interval for the mean of a population with unknown standard deviation, a sample of 24 items is selected

. The mean of the sample is determined to be 23. The number of degrees of freedom for reading the t value is _____. Group of answer choices 21 22 23 24
Mathematics
1 answer:
nikitadnepr [17]2 years ago
5 0

If the sample size of population is 24 then the number of degrees of freedom for reading the t  value is 23 which is option c.

Given sample size of 24,mean 23.

We have to determine the number of degrees of freedom which will be used to find the critical values of t.

Degree of freedom is the number of values in the final calculation of a statistic that are free to vary means that can change their values in the formula of calculating t.

t=(X-μ)/s/\sqrt{n}

where X is sample mean ,

μ is hypothsised population mean

s is sample standard deviation

n is sample size.

Degree of freedom=n-1

In this question n is 24 so the degree of freedom =24-1=23.

Hence the number of degrees of freedom for reading the t value is 23.

Learn more about degree of freedom at brainly.com/question/17305237

#SPJ4

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Hello!


So, this is quite the complex question, and here are the following steps:


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\frac{3(2 -\sqrt[3]{6})\sqrt[3]{9^{2}}}{9} (factor 3 from the expression)

\frac{(2-\sqrt[3]{6})\sqrt[3]{9^{2}}}{3} (reduce the fraction with 3)

\frac{2\sqrt[3]{9^{2}}-\sqrt[3]{9^{2}}}{3} (distributive property)

\frac{2\sqrt[3]{81}-\sqrt[3]{486}}{3} (simplify 3 · 9²)

\frac{6\sqrt[3]{3}-3\sqrt[3]{18}}{3} (simplify the radical)

\frac{3(2\sqrt[3]{3}-3\sqrt[3]{18})}{3} (factor 3 from the expression)

2\sqrt[3]{3}-\sqrt[3]{18} (reduce the fraction)


The answer, is simply, choice A, 2\sqrt[3]{3} -\sqrt[3]{18} ≈ 0.263758.

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Answer:

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Step-by-step explanation:

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