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Butoxors [25]
2 years ago
12

Which list represents the

Chemistry
1 answer:
eduard2 years ago
4 0

The list which represents the

components of the human skeleton is; Bones, tendons, ligaments, cartilage.

<h3>Skeleton</h3>

The human skeleton is defined as the internal framework of the human body. It is made up of 206 bones at adulthood stage and the bone mass in the skeleton makes up about 14%

The skeleton is divided into 2 parts:

  • The axial skeleton: The axial skeleton is the central unit, consisting of the skull, vertebrae, ribs.

  • The appendicular skeleton: It comprise the bones of the extremities

Learn more about skeleton:

brainly.com/question/9332468

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Identify the species oxidized, the species reduced, the oxidizing agent and the reducing agent in the following electron transfe
Vesna [10]

Answer:

In the given chemical reaction:

Species Oxidized: I⁻

Species Reduced: Fe³⁺

Oxidizing agent: Fe³⁺

Reducing agent: I⁻

As the reaction proceeds, electrons are transferred from I⁻ to Fe³⁺

Explanation:

Redox reaction is a chemical reaction involving the simultaneous movement of electrons thereby causing oxidation of one species and reduction of the other species.

The chemical species that <u><em>gets reduced by gaining electrons </em></u><u>is called an </u><u><em>oxidizing agent</em></u>. Whereas, the chemical species that <u><em>gets oxidized by losing electrons </em></u><u>is called a </u><u><em>reducing agent</em></u><u>.</u>

Given redox reaction: 2Fe³⁺ + 2I⁻ → 2Fe²⁺ + I₂

<u>Oxidation half-reaction</u>: 2 I⁻ +  → I₂ + 2 e⁻                 ....(1)

<u>Reduction half-reaction</u>: [ Fe³⁺ + 1 e⁻ → Fe²⁺ ] × 2

                                   ⇒  2 Fe³⁺ + 2 e⁻ → 2 Fe²⁺       ....(2)

In the given redox reaction, <u>Fe³⁺ (oxidation state +3) accepts electrons and gets reduced to Fe²⁺ (oxidation state +2) and I⁻ (oxidation state -1) loses electrons and gets oxidized to I₂ (oxidation state 0).</u>

<u>Therefore, Fe³⁺ is the oxidizing agent and I⁻ is the reducing agent and the electrons are transferred from I⁻ to Fe³⁺.</u>

5 0
3 years ago
Zelda noticed a puddle outside her front door. She saw that the puddle got smaller every day, mil the
Tcecarenko [31]

Explanation:

to set 1 container inside, without air movement. 1 outside in that location. compare the 2 containers to see which container has less or more fluid...

3 0
3 years ago
How many grams of O2 are needed to react with 18.2 g of NH3?
erastova [34]

Answer:

44 g oxygen are needed.

Explanation:

Given data:

Mass of oxygen needed = ?

Mass of ammonia = 18.2 g

Solution:

Chemical equation:

4NH₃ + 5O₂   →  4NO + 6H₂O

Now we will calculate the number of moles of ammonia:

Number of moles = mass/molar mass

Number of moles = 18.2 g/ 17 g/mol

Number of moles = 1.1 mol

Now we will compare the moles of ammonia with oxygen from balance chemical equation.

                        NH₃              :                O₂

                          4                 :                 5

                          1.1                :              5/4×1.1 = 1.375 mol

Mass of oxygen needed:

Mass = number of moles × molar mass

Mass = 1.375 mol × 32 g/mol

Mass = 44 g

4 0
3 years ago
If 27.3% of a sample of silver-112 decays in 1.52 hours, what is the half-life (in hours to 3 decimal places)?
ICE Princess25 [194]

<u>Answer:</u> The half life of the sample of silver-112 is 3.303 hours.

<u>Explanation:</u>

All radioactive decay processes undergoes first order reaction.

To calculate the rate constant for first order reaction, we use the integrated rate law equation for first order, which is:

k=\frac{2.303}{t}\log \frac{[A_o]}{[A]}

where,

k = rate constant = ?

t = time taken = 1.52 hrs

[A_o] = Initial concentration of reactant = 100 g

[A] = Concentration of reactant left after time 't' = [100 - 27.3] = 72.7 g

Putting values in above equation, we get:

k=\frac{2.303}{1.52hrs}\log \frac{100}{72.7}\\\\k= 0.2098hr^{-1}

To calculate the half life period of first order reaction, we use the equation:

t_{1/2}=\frac{0.693}{k}

where,

t_{1/2} = half life period of first order reaction = ?

k = rate constant = 0.2098hr^{-1}

Putting values in above equation, we get:

t_{1/2}=\frac{0.693}{0.2098hr^{-1}}\\\\t_{1/2}=3.303hrs

Hence, the half life of the sample of silver-112 is 3.303 hours.

6 0
3 years ago
Find the volumetric (mL/s) and mass (g/s) flow rates in an artery whose diameter is 0.3 mm and blood flow rate is 25 mm/s.
Setler [38]
I don’t know kid I don’t know ‍♂️
5 0
3 years ago
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