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Butoxors [25]
2 years ago
12

Which list represents the

Chemistry
1 answer:
eduard2 years ago
4 0

The list which represents the

components of the human skeleton is; Bones, tendons, ligaments, cartilage.

<h3>Skeleton</h3>

The human skeleton is defined as the internal framework of the human body. It is made up of 206 bones at adulthood stage and the bone mass in the skeleton makes up about 14%

The skeleton is divided into 2 parts:

  • The axial skeleton: The axial skeleton is the central unit, consisting of the skull, vertebrae, ribs.

  • The appendicular skeleton: It comprise the bones of the extremities

Learn more about skeleton:

brainly.com/question/9332468

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A standard solution of FeSCN2+ is prepared by combining 9.0 mL of 0.20 M Fe(NO3)3 with 1.0 mL of 0.0020 M KSCN . The standard so
Xelga [282]

Answer : The equilibrium concentration of SCN^- in the trial solution is 4.58\times 10^{-8}M

Explanation :

First we have to calculate the initial moles of Fe^{3+} and SCN^-.

\text{Moles of }Fe^{3+}=\text{Concentration of }Fe^{3+}\times \text{Volume of solution}

\text{Moles of }Fe^{3+}=0.20M\times 9.0mL=1.8mmol

and,

\text{Moles of }SCN^-=\text{Concentration of }SCN^-\times \text{Volume of solution}

\text{Moles of }SCN^-=0.0020M\times 1.0mL=0.0020mmol

The given balanced chemical reaction is,

Fe^{3+}(aq)+SCN^-(aq)\rightleftharpoons FeSCN^{2+}(aq)

Since 1 mole of Fe^{3+} reacts with 1 mole of SCN^- to give 1 mole of FeSCN^{2+}

The limiting reagent is, SCN^-

So, the number of moles of FeSCN^{2+} = 0.0020 mmole

Now we have to calculate the concentration of FeSCN^{2+}.

\text{Concentration of }FeSCN^{2+}=\frac{0.0020mmol}{9.0mL+1.0mL}=0.00020M

Using Beer-Lambert's law :

A=\epsilon \times C\times l

where,

A = absorbance of solution

C = concentration of solution

l = path length

\epsilon = molar absorptivity coefficient

\epsilon and l are same for stock solution and dilute solution. So,

\epsilon l=\frac{A}{C}=\frac{0.480}{0.00020M}=2400M^{-1}

For trial solution:

The equilibrium concentration of SCN^- is,

[SCN^-]_{eqm}=[SCN^-]_{initial}-[FeSCN^{2+}]

[SCN^-]_{initial} = 0.00050 M

Now calculate the [FeSCN^{2+}].

C=\frac{A}{\epsilon l}=\frac{0.220}{2400M^{-1}}=9.17\times 10^{-5}M

Now calculate the concentration of SCN^-.

[SCN^-]_{eqm}=[SCN^-]_{initial}-[FeSCN^{2+}]

[SCN^-]_{eqm}=(0.00050M)-(9.17\times 10^{-5}M)

[SCN^-]_{eqm}=4.58\times 10^{-8}M

Therefore, the equilibrium concentration of SCN^- in the trial solution is 4.58\times 10^{-8}M

5 0
3 years ago
How many molecules are in 92.9 g of NaOH?​
kirza4 [7]

2.3226678127494718

this number you could probably simplify to your own standards on your own.

5 0
3 years ago
Identify the atomic orbitals in the C-C sigma bond in ethyne (acetylene HC-triplebond-CH)
aleksley [76]

Answer:

Explanation:

A sigma bond is formed  when a hybrid orbital sp overlaps with another hybrid orbital or with s- or  p- orbital

Ethylene has a structural formula of  H - C≡ C- H

At the ground state; we have :

C    | ⇅ |     |↑ | ↑

        2s       2p

At the excited state, we have:

C    | ↑ |     |↑ | ↑ | ↑

the hybrid orbital

C = | ↑ | ↑ |

      2sp

8 0
4 years ago
Leah is trying to determine how music affects the growth of plants. She hypothesizes that classical music will cause a plant to
Pani-rosa [81]
Leah's experiment:
A. Takes careful and regular measurements (she measures the growth every day)
B. Has a specific hypothesis and a controlled experiment (the music is the only changing variable, the growth conditions are identical, and this is what she wants to test in her hypothesis)
C. Experimental data that can be recorded and analyzed (measuring the growth of plant fits this)

So the answer must be D, since there is no mention of past research that scientists have found on this topic.
8 0
3 years ago
Read 2 more answers
Chromium-51 is a radioactive isotope used to label red blood cells to identify if they remain intact in the body. It has a half-
agasfer [191]
\left[\begin{array}{cccc}0 \ days&27,7days&55,4days&\textbf{83,1days}\\&&&\\0,25mg&0,125mg&0,0625mg&\textbf{0,03125mg}\end{array}\right]
5 0
3 years ago
Read 2 more answers
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