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2 years ago

What is the pressure in a 5.00 L tank with 7.10 moles of oxygen at 39.3 °C?

Chemistry

1 answer:

Katena32 [7]2 years ago

8 0

Answer:

36.4 atm

Explanation:

To find the pressure, you need to use the Ideal Gas Law. The equation looks like this:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = constant (0.0821 L*atm/mol*K)

-----> T = temperature (K)

Before you can plug the given values into the equation, you first need to convert Celsius to Kelvin.

P = ? atm R = 0.0821 L*atm/mol*K

V = 5.00 L T = 393 °C + 273.15 = 312.45 K

n = 7.10 moles

PV = nRT

P(5.00 L) = (7.10 moles)(0.0821 L*atm/mol*K)(312.45 K)

P(5.00 L) = 182.130

P = 36.4 atm

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What mass of CO is needed to react completely with55.0 g of Fe2O3(s)+CO(g) yield Fe(s)+CO2(g)?

Katarina [22]

Answer:

28.9 g

Explanation:

We know that we will need a balanced equation with masses, moles, and molar masses of the compounds involved.

<em>Gather all the information in one place</em> with molar masses above the formulas and masses below them.

$M_{r}$ : 159.69 28.01

Fe₂O₃ + 3CO ⟶ 2Fe + 3CO₂

Mass/g: 55.0

1. Use the molar mass of Fe₂O₃ to calculate the moles of Fe₂O₃.

$\text{Moles of Fe$_{2}$O$_{3}$} =\text{55.0 g Fe$_{2}$O$_{3}$} \times \frac{\text{1 mol Fe$_{2}$O$_{3}$}}{\text{159.69 g Fe$_{2}$O$_{3}$}}= \text{0.3444 mol Fe$_{2}$O$_{3}$}$

2. Use the molar ratio of CO:Fe₂O₃ to calculate the moles of CO.

$\text{Moles of CO} = \text{0.3444 mol Fe$_{2}$O$_{3}$} \times \frac{\text{3 mol CO}}{\text{1 mol Fe$_{2}$O$_{3}$}}= \text{1.033 mol CO}$

3.Use the molar mass of CO to calculate the mass of CO.

$\text{Mass of CO} = \text{1.033 mol CO} \times \frac{\text{28.01 g CO} }{\text{1 mol CO}}= \textbf{28.9 g CO}$

3 0

3 years ago

Read 2 more answers

Which do you think will warm up the plate more quickly?

neonofarm [45]

Answer: B

your welcome Bsbssnsnsmsllqql

3 0

3 years ago

Titration Volume & Concentration

polet [3.4K]

Answer:

18,1 mL of a 0,304M HCl solution.

Explanation:

The neutralization reaction of Ba(OH)₂ with HCl is:

2 HCl + Ba(OH)₂ → BaCl₂ + 2 H₂O

The moles of 17,1 mL≡0,0171L of a 0,161M Ba(OH)₂ solution are:

$0,0171L*\frac{0,161moles}{L}$ = 2,7531x10⁻³moles of Ba(OH)₂

By the neutralization reaction you can see that 2 moles of HCl reacts with 1 mole of Ba(OH)₂. For a complete reaction of 2,7531x10⁻³moles of Ba(OH)₂ you need:

$2,7531x10^{-3}molBa(OH)_{2}*\frac{2molHCl}{1molBa(OH)_{2}}$ = 5,5062x10⁻³moles of HCl.

The volume of a 0,304M HCl solution for a complete neutralization is:

$5,5062x10^{-3}molHCl*\frac{1L}{0,304mol}$ = 0,0181L≡18,1mL

I hope it helps!

4 0

3 years ago

How do solve for density?

Pachacha [2.7K]

Density(D) is defined as Mass(M) divided by Volume(V).

The formula for Density is:

D = M / V.

Another way to remember the formula for Density is to remember "Mass per unit of volume".

I hope this helps!

7 0

3 years ago

A gas under an initial pressure of 0.60 atm is compressed at constant temperature from 27 L to 3.0 L. The final pressure becomes

IRINA_888 [86]

Answer: 5.4

Explanation:

P2 = P1V1/V2

P2 = (.60atm x 27L) / 3.0L = 5.4atm

8 0

3 years ago