Answer:
We need 12.26 grams H2SO4
Explanation:
Step 1: Data given
Volume of a H2SO4 solution = 500 mL = 0.500 L
Concentration of the H2SO4 solution = 0.250 M
Molar mass of H2SO4 = 98.08 g/mol
Step 2: Calculate moles H2SO4
Moles H2SO4 = concentration * volume
Moles H2SO4 = 0.250 M * 0.500 L
Moles H2SO4 = 0.125 moles
Step 3: Calculate mass of H2SO4
Mass of H2SO4 = moles * molar mass
Mass of H2SO4 = 0.125 moles * 98.08 g/mol
Mass of H2SO4 = 12.26 grams
We need 12.26 grams H2SO4
- Due to the inability of the reaction to take place, the yield of 1-Bromobutane would drop.
- Since 1-Butanol won't react with the additional sodium bromide, bromination won't happen.
- If water had been supplied, the equilibrium would have shifted extremely far to the left, preventing the reactants from interacting with the acid and favoring the yield of 1-bromobutane instead.
<h3>What is Bromination?</h3>
- When a substance undergoes bromination, bromine is added to the compound as a result of the chemical reaction.
- After bromination, the result will have different properties from the initial reactant.
- For example, an alkene is brominated by electrophilic addition of
. - Benzene ring bromination by electrophilic aromatic substitution.
Learn more about Bromine here:
brainly.com/question/862562
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The answer is A I’m not 100 percent sure tho
Answer:

Explanation:
= Concentration of stock solution
= Concentration of solution
= Volume of stock solution = 19 mL
= Volume of solution = 0.31 L= 310 mL
We have the relation


The concentration of the diluted solution will be 0.613 times the concentration of the stock solution.
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