Answer and Explanation:
Isotopes are same in atomic number and different in atomic mass. Isotopes have same number of electron and proton but different number of neutron and due to same proton their atomic numbers are same and due to different number of neutron their atomic mass are different because neutron also take part in atomic mass
Answer:
The concentration of the Cu2 in the 100.0 ml volumetric flask is 0.0592 M
Explanation:
In the first dilution, Cu2 was diluted ten times (25 / 250 = 1/10). Then, this dilution was diluted again, but now five times (20 / 100 = 1/5). In total, the solution was diluted 50 times (1/10 * 1/5 = 1/50). The final concentration will be 2.96 M / 50 = 0.0592 M
The presence of a large population of sludgeworms indicates water depleted of oxygen and a high level of organic pollution.
The sludgeworms Tubifex is harvested and sold as tropical fish food since it is common near sewer outlets and serves as a sign of water or organic pollution. Polychaetes are crucial in rearranging the silt on the ocean floor.
Organic contamination happens when too much organic material, such sewage or manure, gets into the water.
There will be more decomposers and sludgeworms in a pond as the organic content accumulates. These decomposers and sludgeworms develop quickly and consume a lot of oxygen as they do so.
Hence, Sludgeworms are a sign of an abundance of oxygen-depleted water and significant levels of organic pollutants.
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Answer: The concentration of Silver Nitrate in solution # 4 is 3.5x10-6 M
Explanation:
When calculating the concentration of a dilute solution, we use the equation:
C1V1 = C2V2
Where C1 = concentration of the known solution
V1= amount of know solution
C2= new concentration
V2= capacity of the flask
Keep in mind that solution #2 is not related to the preparation of solutions #3 y #4, so the concentration of #2 is irrelevant.
For calculating the concentration of solution #4 , we first calculate the concentration of the solution #3, that comes from the solution #1.
- Calculating concentration solution #3
- C1V1 = C3V3
- C3= (0.0002442 M * 10mL) / 250mL
- C3= 9.8X10-6M
2. Calculating concentration solution #4
- C3V3 = C4V4
- C4= (9.8X10-6M *18mL) / 50mL
- C4= 3.5X10-6 M