All categories

2 years ago

A 2 kg cat is stuck in a tree 10 m above the ground. How much GPE does it have?

Chemistry

1 answer:

Dovator [93]2 years ago

3 0

Answer:

196J, but C. at 200 J comes close.

Explanation:

Potential energy due to gravity is given by:

PEgrav = mass • g • height

where g is the acceleration due to gravity. We'll use 9.8 N/kg (on Earth).

PEgrav = mass • g • height

PEgrav = (2 kg) • (9.8 N/kg) • (10 m)

PEgrav = 196 N*m

1 N*m = 1 Joule

PEgrav = 196 J

C. at 200 J comes close. The solution probably used a value of g equal to 10 N/kg)

You might be interested in

20 POINTS IF YOU CAN ANSWER THIS CORRECTLY, PLEASE!

xeze [42]

Answer: a

Explanation: trust me

7 0

3 years ago

A nuclear fission reaction has mass difference between the products and the reactants of 0.0284 amu. Calculate the

notsponge [240]

Answer:

C) 4.24 x $10^{-12}$

Explanation:

E = Δm $c^{2}$

Δm = 0.0284 x 1.66 x $10^{-27}$ kg = 4.714x $10^{-29}$ kg

putting value in above equation

E = 4.714x $10^{-29}$ kg x (3x $10^{8}$ $)^{2}$ = 4.24 x $10^{-12}$

6 0

2 years ago

Which material is likely to slow the flow of electric charges the most? Explain

vesna_86 [32]

Answer:

The material that would most likely slow the flow of electricity is plastic.

Explanation:

Plastic is a conductor. A conductor is something that stop or slows down the flow of electricity.

4 0

2 years ago

How many moles of water would form the reaction of exactly 58.3 grams of magnesium hydroxide

Marat540 [252]

Answer:

$\boxed{\text{2.00 mol}}$

Explanation:

We know we will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

You don't tell us what the reaction is, but we can solve the problem so long as we balance the OH.

M_r: 58.32

Mg(OH)₂ + … ⟶ … + 2HOH

m/g: 58.3

(a) Moles of Mg(OH)₂

$\text{Moles of Mg(OH)$_{2}$} =\text{58.3 g Mg(OH)$_{2}$} \times \dfrac{\text{1 mol Mg(OH)$_{2}$}}{\text{58.32 g Mg(OH)$_{2}$}}\\\\=\text{0.9997 mol Mg(OH)$_{2}$}$

(b) Moles of H₂O

The molar ratio is 2 mol H₂O = 1 mol Mg(OH)₂.

$\text{Moles of H$_{2}$O}= \text{0.9995 mol Mg(OH)$_{2}$} \times \dfrac{\text{2 mol {H$_{2}$O}}}{ \text{1 mol Mg(OH)$_{2}$}}\\\\= \textbf{2.00 mol H$_{2}$O}$

The reaction will form $\boxed{\textbf{2.00 mol}}$ of water.

6 0

3 years ago

0.0027432 using scientific notation

alexira [117]

Answer: 2.7423 × 10^-3

Explanation:

4 0

3 years ago