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Travka [436]
3 years ago
14

when a metal, such as lead, is oxidied (loses electrons) to form a positive ion (cation), how does he solubility change?

Engineering
1 answer:
o-na [289]3 years ago
8 0

Answer: The size of the ion and the charge of the ion are the factors that affect solubility in water.

Explanation:

Lead lose electrons to become cations. Compounds with small ions tend to be less soluble than compounds with large ions. Large ions have higher solubility. This is because small ions are closely packed so it is difficult for water to break them apart.

Compounds with small ions seemingly have less solubility than those with large ions. The ions in the compound attract each other, and the water molecules attract the ions. Compounds would be soluble in water If the water molecules have a greater or higher attraction to the ions than ions have for each other.

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Can anyone tell me what rock this is?
Oksi-84 [34.3K]

Answer: answer is B

Explanation:

8 0
3 years ago
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A cone-shaped part is to be fabricated using stereolithography. The radius of the cone at its base = 35 mm, and its height = 50
iren [92.7K]

Explanation:

volume = πR²h/3

= πx35²x50/3

= 192325/3

= 64166.725

number of layers n = 50mm/0.05

n = 1000layers

average volume = 64166.725/1000

= 64.167mm³

average area = 64.167/0.05

= 1283.34mm²

average time = 1283.34/900mm x 0.22

= 6.48

6.48 + 15 seconds

= 21.48 seconds

time required = 1000x21.48

= 21480 seconds

convert to minutes

21480/60

= 358 minutes

21480/3600

= 5.967 hours

8 0
3 years ago
The function below takes a two parameters: a list called a_list and a value called a_value. Complete the function to first check
Alik [6]

Explanation:

def checklist(a_list, a_value):// def //used to name a function, the //arguments being passed into the //functions are a_list and a_value

if a_value in list://if statement to

//check if it's in the list or not

print("")//print statement to do

//nothing

else://else statement for if the

//a_value is in a_list

a_list.append(a_value)//this adds

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5 0
3 years ago
g A primary sedimentation basin is designed for an average flow of 0.3 m3/s. The TSS concentration in the influent is 240 mg/L.
yarga [219]

Answer:

(a) 0.243 m3/day

(b) 96 mg/l

(c) 0.426 m3/min

Explanation:

The sludge has an average solids concentration of 4 percent and considering TSS concentration in the influent of 240 mg/L then solids in sludge will be 0.04*240= 9.6 mg/L

Considering the average flow of 0.3 m3/s then mass of sludge per day will be given by 0.3*1000*9.6*60*60*24/1000000=248.832 kg/day

To get volume, considering specific gravity given as 1.025 and taking density of water as 1000 kg/m3 then density of sludge is 1025 kg/m3

Volume is mass/density hence 248.832/1025=0.2427629268292 m3/day

Approximately, the volume of sludge is 0.243 m3/day.

(b)

Efficiency of 60 percent is equivalent to 0.6

Efficiency=(influent concentration- flow rate)/influent concentration

0.6=(240-flow rate)/240

Flow rate= 96 mg/l

(c)

Cycle time= 0.243/0.57=0.4263157894736 m3/min

Rounded off, cycle time is 0.426 m3/day

3 0
3 years ago
Su prepares a presentation about the industrial revolution. She wants to change the font on the second slide of her presentation
choli [55]

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Explanation

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2. Font- As the various options are available on the screen such as  font size , add image etc ,click on the option "Font"

3. Drop Down- As you click on font option , it will be followed by a drop down option with various type of fonts. Su can select the font she wishes to add in her presentation and look it more precise by adjusting the Font Size.

4 Save- Save the changes made in the slide for future.        

8 0
2 years ago
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