Consider a circuit element, with terminals a and b, that has vab= -12V and iab= 3A. Over a period of 2 seconds, how much charge
1 answer:
Answer:
a) 6 coulombs
b) The electrons carrying the charge will enter at point b with respect to element and this is because electrons follow in opposite direction of current
c) = -72 joules
Energy is taken from element
Explanation:
Given data:
V ab = -12 v
I ab = 3A
period ( t ) = 2 seconds
a) determine how much charge moves through the element
q = I * t
= 3 * 2 = 6 coulombs
b) The electrons carrying the charge will enter at point b with respect to element and this is because electrons follow in opposite direction of current
c) determine how much energy is transferred
= Vab * Iab * t
= -12 * 3 * 2
= -72 joules
Energy is taken from element
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Answer:
check the explanation
Explanation:
1.
Thickness Loss =
Hence Rate of Corrosion = = 0.03 inches per year
2.
As the expected future life is 7 years,
40 carbon steel pipe has to be replaced every 3 years as given in the question,
Cost per unit length is the sum of material cost and installation cost.
Cost of 40 carbon steel = (5 dollars + 16.5 dollars) * 3 = 64.5 dollars
For 80 carbon steel pipe, first calculate the thickness loss,
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This 80 carbon steel pipe has to be replaced one more time
Hence, Cost per unit length is the sum of material cost and installation cost.
Cost of 80 carbon steel = (8.3 dollars + 16.5 dollars) * 2 = 49.6 dollars
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Answer:
a) aA = - 13.33 mm/s²
aB = - 20 mm/s²
b) aD = - 13.33 mm/s²
c) vB = 70 mm/s
d) xB = 440 mm
Explanation:
Given
The initial speed of B is: v₀B = 150 mm/s
Distance moved by A is: xA = 240 mm
Velocity of A is: vA = 60 mm/s
Assuming:
Displacement of blocks are denoted by:
A = xA
B = xB
C = xC
D = xD
From the pic shown, the total length of the cable is:
xB + (xB - xA) + 2*(d - xA) = L
⇒ 2*xB - 3*xA = L - 2*d
where L - 2*d is constant. Differentiating the above equation with respect to time:
d(2*xB)/dt - d(3*xA)/dt = 0
⇒ 2*vB - 3*vA = 0 (i)
Substituting in equation (i)
2*(150 mm/s) - 3*vA = 0
⇒ v₀A = 100 mm/s (initial speed of A)
Then, we use the equation
vA² = v₀A² + 2*aA*xA
Substituting the values in above equation:
(60 mm/s)² = (100 mm/s)² + 2*aA*(240 mm)
⇒ aA = - 13.33 mm/s²
If 2*vB - 3*vA = 0
Differentiating the above equation with respect to time:
d(2*vB)/dt - d(3*vA)/dt = 0
⇒ 2*aB - 3*aA = 0 (ii)
Substituting in equation (ii)
2*aB - 3*(- 13.33 mm/s²) = 0
⇒ aB = - 20 mm/s²
b) From the pic shown,
xD - xA = constant
If we apply
d(xD)/dt - d(xA)/dt = 0
⇒ vD - vA = 0
then
d(vD)/dt - d(vA)/dt = 0
⇒ aD - aA = 0
⇒ aD = aA = - 13.33 mm/s²
c) We use the formula
vB = v₀B + aB*t
Substituting the values in above equation:
vB = 150 mm/s + (- 20 mm/s²)*(4 s)
⇒ vB = 70 mm/s
d) We apply the equation
xB = v₀B*t + 0.5*aB*t²
Substituting the values in above equation:
xB = (150 mm/s)*(4 s) + 0.5*(- 20 mm/s²)*(4 s)²
⇒ xB = 440 mm
