Consider a circuit element, with terminals a and b, that has vab= -12V and iab= 3A. Over a period of 2 seconds, how much charge
1 answer:
Answer:
a) 6 coulombs
b) The electrons carrying the charge will enter at point b with respect to element and this is because electrons follow in opposite direction of current
c) = -72 joules
Energy is taken from element
Explanation:
Given data:
V ab = -12 v
I ab = 3A
period ( t ) = 2 seconds
a) determine how much charge moves through the element
q = I * t
= 3 * 2 = 6 coulombs
b) The electrons carrying the charge will enter at point b with respect to element and this is because electrons follow in opposite direction of current
c) determine how much energy is transferred
= Vab * Iab * t
= -12 * 3 * 2
= -72 joules
Energy is taken from element
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This question is incomplete, the missing image in uploaded along this answer below.
Answer:
The required stress is 200 Mpa
Explanation:
Given the data in the question;
diameter D = 12 mm = 12 × 10⁻³ m
Length L = 188 mm = 188 × 10⁻³ m
Poisson's ratio v = 0.34
Reduction in diameter Δd = 0.0105 mm = 0.0105 × 10⁻³ m
The transverse strain will;
εˣ = Δd / D
εˣ = -0.0105 × 10⁻³ / 12 × 10⁻³ m
εˣ = -0.00088
The longitudinal strain will be;
= - ( εˣ / v )
= - ( -0.00088 / 0.34 )
= - ( - 0.002588 )
= 0.0026
Now, Using the values for strain, we get the value of stress from the graph provided in the question, ( first image uploaded below.
From the graph, in the Second image;
The stress is 200 Mpa
Therefore, The required stress is 200 Mpa
