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nalin [4]
2 years ago
15

Look at picture for the question

Chemistry
1 answer:
4vir4ik [10]2 years ago
3 0

The amount, in grams, of carbon tetrachloride that would be present, will be 22.99 grams.

<h3>Finding the mass from the number of particles</h3>

For every one mole of any substance, there are 6.022 x 10^{23} atoms of particles. This is according to Avogadro.

Now, there are 9 x 10^{22 particles in this particular carbon tetrachloride.

If 1 mole = 6.022 x 10^{23} particles

Then,

9 x 10^{22 particles =  9 x 10^{22 x 1/6.022 x 10^{23} particles

                       = 0.1495 moles

Carbon tetrachloride has the chemical formula CCl4 and has a molar mass of 153.82 g/mol.

Recall that: mole = mass/molar mass

Hence, mass = mole x molar mass.

Mass of 0.1495 moles CCl4 = 0.1495 x 153.82 = 22.99 grams

More on number of atoms of substances can be found here: brainly.com/question/1445383

#SPJ1

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Consider the system at equilibrium. 2 H 2 ( g ) + S 2 ( g ) − ⇀ ↽ − 2 H 2 S ( g ) How will increasing the concentration of S 2 s
borishaifa [10]

Answer:

1) the balance will shift to the right

2) the balance will shift to the left

3) There will be no effect on the position of the equilibrium.

Explanation:

Step 1: Data given

The Principle of Le Chatelier says 'If the concentration of one of the reaction partners changes, the balance will shift to counteract that concentration change.

Step 2: The balanced equation

2H2(g) + S2(g) ⇆ 2H2S(g)

Step 3: How will increasing the concentration of S2 shift the equilibrium?

If the S2 concentration is increased, the system will attempt to undo that change in concentration by shifting the balance to the right, and so the H2S concentration will increase.

Step 4: How will increasing the concentration of H2S shift the equilibrium?

If the H2S concentration is increased, the system will attempt to undo that change in concentration by shifting the balance to the left, and so the H2 and S2 concentration will increase.

Step 5: How will adding a catalyst shift the equilibrium?

Reactions can be sped up by the addition of a catalyst.

In the presence of a catalyst, both the forward and reverse reaction rates will speed up equally, thereby allowing the system to reach equilibrium faster.

Adding a catalyst makes absolutely no difference to the position of equilibrium.

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PLS HELP FOR BRA.INLIEST
snow_tiger [21]
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How the hydrosphere and biosphere interact in this swamp?
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heat from the sun and heat flowing out of earth as it cools.

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1. In_____particles are in contact with each other.
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The overall reaction taking place is shown in the equation below
algol [13]

A. The maximum possible mass of sodium that can be produced is 47.18 Kg

B. The percentage yield of the reaction is 80.6%

<h3>Determination of the mass of NaCl and Na </h3>

We'll begin by calculating the mass of NaCl that reacted and the mass of Na obtained from the balanced equation.

2NaCl –> 2Na + Cl₂

Molar mass NaCl = 23 + 35.5 = 58.5 g/mol

Mass of NaCl from the balanced equation = 2 × 58.5 = 117 g = 117 / 1000 = 0.117 Kg

Molar mass of Na = 23 g/mol

Mass of Na from the balanced equation = 2 × 23 = 46 g = 46 / 1000 = 0.046 Kg

SUMMARY

From the balanced equation above,

0.117 Kg of NaCl reacted to produce 0.046 Kg of Na.

<h3>A. How to determine mass of Na produced </h3>

From the balanced equation above,

0.117 Kg of NaCl reacted to produce 0.046 Kg of Na.

Therefore,

120 Kg of NaCl will react to produce = (120 × 0.046) / 0.117 = 47.18 Kg of Na

Thus, the maximum mass of Na produced is 47.18 Kg.

<h3>B. How to determine the percentage yield </h3>
  • Actual yield = 38.05 Kg
  • Theoretical yield = 47.18 Kg
  • Percentage yield =?

Percentage yield = (Actual / Theoretical) × 100

Percentage yield = (38.05 / 47.18) × 100

Percentage yield = 80.6%

Learn more about stoichiometry:

brainly.com/question/14735801

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