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valkas [14]
2 years ago
12

Calculate the frequency of light having a wavelength of 425nm. remember that 1nm=1×10−9m

Chemistry
1 answer:
Gnom [1K]2 years ago
8 0

The frequency of light having a wavelength of 425nm will be 70588 × 10^{14} Hz.

The count of times an event takes place per unit of time is known as its frequency. The word frequency would be most frequently used to describe waves in physics including chemistry, including light, sound, including radio waves. The frequency refers to the number of times during one second that a point on a wave crosses a fixed reference point.

A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places  in the consecutive cycles.

Given data:

wavelength = 425nm = 425 * 10^{-9} m

Frequency can be calculated by using the formula;

Frequency =  speed of light / wavelength

Frequency = 3 × 10^{8} m/s / 425 × 10^{-9} m = 7,0588 × 10^{14} Hz.

Therefore, the frequency of light having a wavelength of 425nm will be 70588 × 10^{14} Hz.

To know more about  frequency

brainly.com/question/18651058

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2 years ago
The vapor pressure of pure water at 25 °c is 23.8 torr. What is the vapor pressure (torr) of water above a solution prepared by
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The vapour pressure of the solution is 23.4 torr.

Use <em>Raoult’s Law</em> to calculate the vapour pressure:  

<em>p</em>₁ = χ₁<em>p</em>₁°  

where  

χ₁ = the mole fraction of the solvent  

<em>p</em>₁ and <em>p</em>₁° are the vapour pressures of the solution and of the pure solvent  

The formula for vapour pressure lowering Δ<em>p</em> is  

Δ<em>p</em> = <em>p</em>₁° - <em>p</em>₁  

Δ<em>p</em> = <em>p</em>₁° - χ₁<em>p</em>₁° = p₁°(1 – χ₁) = χ₂<em>p</em>₁°  

where χ₂ is the mole fraction of the solute.  

<em>Step 1</em>. Calculate the <em>mole fraction of glucose </em>

<em>n</em>₂ = 18.0 g glu × (1 moL glu/180.0 g glu) = 0.1000 mol glu  

<em>n</em>₁ = 95.0 g H_2O × (1 mol H_2O/18.02 g H_2O) = 5.272 mol H_2O  

χ₂ = <em>n</em>₂/(<em>n</em>₁ + n₂) = 0.1000/(0.1000 + 5.272) = 0.1000/5.372 = 0.018 62  

<em>Step 2</em>. Calculate the <em>vapour pressure lowering</em>  

Δ<em>p</em> = χ₂<em>p</em>₁° = 0.018 62 × 23.8 torr = 0.4430 torr  

<em>Step 3</em>. Calculate the <em>vapour pressure</em>  

<em>p₁</em> = <em>p</em>₁° - Δ<em>p</em> = 23.8 torr – 0.4430 torr = 23.4 torr

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3 years ago
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Answer:

I dont know

Explanation:

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Explanation:

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