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2 years ago

Calculate the frequency of light having a wavelength of 425nm. remember that 1nm=1×10−9m

Chemistry

1 answer:

Gnom [1K]2 years ago

8 0

The frequency of light having a wavelength of 425nm will be 70588 × $10^{14} Hz$ .

The count of times an event takes place per unit of time is known as its frequency. The word frequency would be most frequently used to describe waves in physics including chemistry, including light, sound, including radio waves. The frequency refers to the number of times during one second that a point on a wave crosses a fixed reference point.

A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places in the consecutive cycles.

Given data:

wavelength = 425nm = $425 * 10^{-9} m$

Frequency can be calculated by using the formula;

Frequency = speed of light / wavelength

Frequency = 3 × $10^{8} m/s$ / 425 × $10^{-9} m$ = 7,0588 × $10^{14} Hz$ .

Therefore, the frequency of light having a wavelength of 425nm will be 70588 × $10^{14} Hz$ .

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If a gas occupies 1532.7 mL at standard temperature, what volume does it occupy at 49.4 ºC if the pressure remains constant?

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a. 1810mL

Explanation:

When conditions for a gas change under constant pressure (and the number of molecules doesn't change), it follows Charles' Law:

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To convert from Celsius to Kelvin, add 273, or use the equation: $T_C+273=T_K$

For this problem, one must also recall that standard temperature is 0°C (or 273K).

So, $T_1 = 273[K]$ , and $T_2 = (49.4+273)[K]=322.4[K]$ .

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$\dfrac{(1532.7[mL])}{(273[K])}=\dfrac{V_2}{(322.4[K])}$

$\dfrac{(1532.7[mL])}{(273[K\!\!\!\!\!{-}])}(322.4[K\!\!\!\!\!{-}] )=\dfrac{V_2}{(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})}(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})$