Question

The vapor pressure of pure pentane and pure hexane are 425 torr and 151 torr respectively. equal moles of pentane and hexane are mixed. what is the mole fraction of pentane in the vapor?

Answer 1

The mole fraction of pentane in the vapor is 0.291

Vapour pressure rises with temperature and is a measurement of a substance's propensity to transform into a gaseous or vapour state. The boiling point of a liquid is the temperature at which the pressure exerted by its surroundings equals the vapour pressure present at the liquid's surface.

The number of moles of a particular component in the solution divided by the overall number of moles in the sample solution is known as the mole fraction.

Using the formula for vapour pressure,

vapour pressure = $P^{}$°$_{hex}$ × $X_{hex}$ + $P^{}$°$_{pen}$ × $X_{pen}$

vapour pressure = 151 ×  $(1-$$X_{pen}$$)$ + 425 × $X_{pen}$

240 = 151 - 151$X_{pen}$ + 425$X_{pen}$

240 - 151 = -  151$X_{pen}$ + 425 $X_{pen}$

89 = 274 $X_{pen}$

$\frac{89}{274}$ = $X_{pen}$

0.291 = $X_{pen}$

Therefore,  the mole fraction of pentane in the vapor is 0.291

Learn more about vapour pressure here;

brainly.com/question/25699778

#SPJ4