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Liono4ka [1.6K]
2 years ago
10

The peak current through a resistor is 2. 0 aa. part a what is the peak current if the resistance rr is doubled?

Physics
1 answer:
timofeeve [1]2 years ago
8 0

When the resistance R is doubled, I = 1 A

One of the most fundamental and significant principles controlling electrical and electronic circuits is called Ohm's Law. For a linear device, it relates current, voltage, and resistance.

According to Ohm's Law, the current flowing through a circuit is inversely proportional to the resistance in the circuit and directly proportional to the applied potential difference.

Ohm's law can be written mathematically as follows:

V = IR

Where:

   V = voltage expressed in Volts

   I = current expressed in Amps

   R = resistance expressed in Ohms

If any two quantities are known, the third can be computed by manipulating the formula.

   I= V/R

   R= V/I

To know more about Ohm's law refer:

brainly.com/question/796939

#SPJ4

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The photometer is a device that converts light to voltage which is read out by the digital multimeter (DMM). This is due to the
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Answer:

It converts light into electric current.

Explanation:

The first line of the description says that the photometer is a device that converts light to voltage. if the voltage can be measured then current flowing through it can be calculated by Ohms law V=IR.

<em>Hence the photometer converts light to electric current.</em>

The photometer is used to measure the strength of electromagnetic radiation falling on it and operate within the range of ultraviolet ,visible and infrared spectrum.

It converts light to electric current using photodiode (pn junction),photoresistor and photmultiplier.

 

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A bungee jumper jumps off a bridge and bounces up and down several times.
Stella [2.4K]

The energy that was lost due to air resistance while she was bouncing is determined as 3,360 J.

<h3>Conservation of energy</h3>

The amount of energy lost due to  air resistance while she was bouncing is determined from the principle of conservation of energy.

ΔE = P.E - Ux

ΔE = mgh - ¹/₂kx²

ΔE = (50)(9.8)(16) - ¹/₂(35)(16)²

ΔE = 3,360 J

Thus, the energy that was lost due to air resistance while she was bouncing is determined as 3,360 J.

Learn more about energy here: brainly.com/question/13881533

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