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2 years ago

The peak current through a resistor is 2. 0 aa. part a what is the peak current if the resistance rr is doubled?

Physics

1 answer:

timofeeve [1]2 years ago

8 0

When the resistance R is doubled, I = 1 A

One of the most fundamental and significant principles controlling electrical and electronic circuits is called Ohm's Law. For a linear device, it relates current, voltage, and resistance.

According to Ohm's Law, the current flowing through a circuit is inversely proportional to the resistance in the circuit and directly proportional to the applied potential difference.

Ohm's law can be written mathematically as follows:

V = IR

Where:

V = voltage expressed in Volts

I = current expressed in Amps

R = resistance expressed in Ohms

If any two quantities are known, the third can be computed by manipulating the formula.

I= V/R

R= V/I

To know more about Ohm's law refer:

brainly.com/question/796939

#SPJ4

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An unbalanced force is defined as a force that __________. allows an object to remain at rest cause an object to accelerate in a

fredd [130]

cause an object to accelerate in a direction opposite to the unbalanced force

Explanation:

An unbalanced force is defined as any force that causes an object to accelerate in a direction opposite to the unbalanced force.

The unbalanced force is the net or resultant force describe in newton's second law of motion.

In the first law, it is the external force that causes the motion of a body to change.

Unbalanced forces can cause body to either accelerate in the direction of the force or in an opposite direction of the force.

learn more:

Newton laws brainly.com/question/11411375

#learnwithBrainly

5 0

3 years ago

Read 2 more answers

A new planet is discovered that has twice the Earth's mass and twice the Earth's radius. On the surface of this new planet a per

kirza4 [7]

Answer:

option B

Explanation:

Radius of new planet,R' = 2R

Mass of the earth, M' = 2 M

R and M is the Radius and Mass of the earth.

Weight of the person on earth = 500 N

Weight of the person in the new planet = ?

We know acceleration due to gravity is calculated by using formula

$g = \dfrac{GM}{R^2}$

now, acceleration due to gravity on the new planet

$g' = \dfrac{GM'}{R'^2}$

$g' = \dfrac{G(2M)}{(2R)^2}$

$g' =\dfrac{1}{2} \dfrac{GM}{R^2}$

$g' =\dfrac{g}{2}$

here acceleration due to gravity is half in new planet, so weight will also be half on the new planet.

Weight on the new plane is equal to $\dfrac{500}{2}$ = 250 N

correct answer is option B

5 0

3 years ago

Consider a spherical planet of uniform density rho. The distance from the planet's center to its surface (i.e., the planet's rad

alisha [4.7K]

Answer:

a) $g(r) = 4\pi \cdot G \cdot \rho\cdot r$ , b) $g = 4\pi \cdot G \cdot \rho\cdot r_{P}$

Explanation:

a) The acceleration due to gravity inside the planet is:

$dg = G\cdot \frac{\rho \cdot dV}{r^{2}}$

$dg = G\cdot \frac{4\pi\cdot \rho \cdot r^{2}\,dr}{r^{2}}$

$dg = 4\pi\cdot G\cdot \rho \,dr$

$g(r) = 4\pi \cdot G \cdot \rho\cdot r$

b) The acceleration at the surface of the planet is:

$g = 4\pi \cdot G \cdot \rho\cdot r_{P}$

5 0

3 years ago

If it takes a ball dropped from rest 2.261 s to fall to the ground, from what height H was it released? Express your answer in m

algol [13]

Answer:

Height, H = 25.04 meters

Explanation:

Initially the ball is at rest, u = 0

Time taken to fall to the ground, t = 2.261 s

Let H is the height from which the ball is released. It can be calculated using the second equation of motion as :

$H=ut+\dfrac{1}{2}at^2$

Here, a = g

$H=\dfrac{1}{2}gt^2$

$H=\dfrac{1}{2}\times 9.8\times (2.261)^2$

H = 25.04 meters

So, the ball is released form a height of 25.04 meters. Hence, this is the required solution.

7 0

3 years ago

A high-speed K0 meson is traveling at β = 0.90 when it decays into a π + and a π − meson. What are the greatest and least speeds

san4es73 [151]

Answer:

greatest speed=0.99c

least speed=0.283c

Explanation:

To solve this problem, we have to go to frame of center of mass.

Total available energy fo π + and π - mesons will be difference in their rest energy:

$E_{0,K_{0} }-2E_{0,\pi } =497Mev-2*139.5Mev\\$

=218 Mev

now we have to assume that both meson have same kinetic energy so each will have K=109 Mev from following equation for kinetic energy we have,

K=(γ-1) $E_{0,\pi }$

$K=E_{0,\pi}(\frac{1}{\sqrt{1-\beta ^{2} } } -1)\\\frac{1}\sqrt{1-\beta ^{2} }}=\frac{K}{E_{0,\pi}}+1\\ {1-\beta ^{2}=\frac{1}{(\frac{K}{E_{0,\pi}}+1)^2}}\\\beta ^{2}=1-\frac{1}{(\frac{K}{E_{0,\pi}}+1)^2}}\\\beta = +-\sqrt{\frac{1}{(\frac{K}{E_{0,\pi}}+1)^2}}\\\\\\beta =+-\sqrt{1-\frac{1}{(\frac{109Mev}{139.5Mev+1)^2}}$

$u'=+-0.283c$

note +-=±

To find speed least and greatest speed of meson we would use relativistic velocity addition equations:

$u=\frac{u'+v}{1+\frac{v}{c^{2} } } u'\\u_{max} =\frac{u'_{+} +v_{} }{1+\frac{v}{c^{2} } } u'_{+} \\u_{max} =\frac{0.828c +0.9c }{1+\frac{0.9c}{c^{2} } } 0.828\\ u_{max} =0.99c\\u_{min} =\frac{u'_{-} +v_{} }{1+\frac{v}{c^{2} } } u'_{-}\\u_{min} =\frac{-0.828c +0.9c }{1+\frac{0.9c}{c^{2} } } -0.828c\\u_{min} =0.283c$

6 0

3 years ago