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Kryger [21]
3 years ago
10

A body of mass 500kg moving at a speed of 10m/s reaches the speed of 50m/s in 20s.The force exerted is

Physics
1 answer:
Leona [35]3 years ago
6 0

Answer:

answer is 1000 N

formula used-

<em><u>F= m x (v-u/t)</u></em>

<em><u>mark</u></em><em><u> </u></em><em><u>th</u></em><em><u>is</u></em><em><u> as</u></em><em><u> brainliest</u></em><em><u>!</u></em>

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A circular test track for cars has a circumference of 3.5 kmkm . A car travels around the track from the southernmost point to t
elixir [45]

Answer:

(A) Distance will be equal to 1.75 km

(B) Displacement will be equal to 1.114 km

Explanation:

We have given circumference of the circular track = 3.5 km

Circumference is given by 2\pi r=3.5

r = 0.557 km

(a) It is given that car travels from southernmost point to the northernmost point.

For this car have to travel the distance equal to semi perimeter of the circular track

So distance will be equal to =\frac{3.5}{2}=1.75km

(b) If car go along the diameter of the circular track then it will also go from southernmost point to the northernmost point. and it will be equal to diameter of the track

So displacement will be equal to d = 2×0.557 = 1.114 m

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3 years ago
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Which equation describes the cosines function for right triangle?
Bogdan [553]

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Explanation:

8 0
4 years ago
21. A toy car starts from rest and begins to
Bond [772]

Answer:

v = 66 m/s

Explanation:

Given that,

The initial velocity of a car, u = 0

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Let v is the final velocity. It can be calculated using first equation of motion. It is given by :

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