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BabaBlast [244]
2 years ago
14

Help with i) and ii) pls >_

Physics
2 answers:
alina1380 [7]2 years ago
4 0

Answer:

4 it the corrcert anser

Explanation:

Naya [18.7K]2 years ago
3 0
The correct answer has to be 4
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Assume you are a perfect blackbody at a temperature of T = 310 K. What is the rate, in watts, at which you radiate energy? (For
madreJ [45]

Answer:

P = 942.54 W

Explanation:

Given:

Temperature, T = 310 K

mass, m = 70 kg

Now from the stefan's law,

we have the formula

P = σAT⁴

where,

P = radiate energy

σ = Stefan's constant = 5.67 × 10⁻⁸ W/(m² K⁴)

A = Area of the body

Average surface area for a human body = 1.8 m²

T = Temperature

on substituting the values we get,

P = 5.67 × 10⁻⁸ × 1.8 × 310⁴

or

P = 942.54 W

7 0
3 years ago
A thin spherical shell with radius R1 = 4.00 cm is concentric with a larger thin spherical shell with radius R2 = 6.00 cm . Both
kakasveta [241]

Answer:

The right response will be "450 volts".

Explanation:

The given values are:

R1 = 4.00 cm

R2 = 6.00 cm

q1 = +6.00 nC

q2 = −9.00 nC

As we know,

The potential difference between the two shell's difference will be:

⇒  \Delta V=K[(\frac{q1}{R1}+\frac{q2}{R2})-(\frac{q1}{R1} +(\frac{q2}{R2}))]

           =K[\frac{q1}{R2}-\frac{q1}{R1} ]

On substituting the values, we get

           =(9\times 10^9)[\frac{6\times 10^{-9}}{0.04}-\frac{6\times 10^{-9}}{0.06}]  

       Δ =450 \ volts

3 0
3 years ago
The study of blank involves the study of the natural world
RUDIKE [14]
The study of science involves the study of the natural world.
3 0
2 years ago
Two positive charges of 20 micro coulomb and 100 micro coulomb and the distance between them is 150cm.What will be the electrica
Roman55 [17]

Answer:

0.8 N

Explanation:

From coulomb's law,

Formula:

F = kqq'/r²........................ Equation 1

Where F = Force of repulsion, k = coulomb's constant, q = first positive charge, q' = second positive charge, r = distance between the charge.

Given: q = 20 μC = 20×10⁻⁶ C, q' = 100 μC = 100×10⁻⁶ C, r = 150 cm = 1.5 m.

Constant:  k = 9×10⁹ Nm²/C²

Substitute these values into equation 1

F = (20×10⁻⁶ )( 100×10⁻⁶)(9×10⁹)/1.5²

F = 1800×10⁻³/2.25

F = 1.8/2.25

F = 0.8 N

3 0
3 years ago
You are pushing on a heavy desk with a force of 65 N the desk does not slide the force of friction between the desk and the floo
astra-53 [7]

When an object does not move even on pushing , static frictional force acts on in opposite direction of the applied force to stop the object from moving. static frictional force is a self adjusting force and it adjust its value according to the applied force if the applied force is smaller than the maximum value of static frictional force. The object starts moving once the applied force on it becomes greater than the maximum static frictional force.  hence the statement is true.

7 0
3 years ago
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