Mitosis is a stage of the cell cycle
Answer:
-3.82ºC is the freezing point of solution
Explanation:
We work with the Freezing point depression to solve the problem
ΔT = m . Kf . i
ΔT = Freezing point of pure solvent - freezing point of solution
Let's find out m, molality (moles of solute in 1kg of solvent)
15 g / 58.45 g/mol = 0.257 moles of NaCl
NaCl(s) → Na⁺ (aq) + Cl⁻(aq)
i = 2 (Van't Hoff factor, numbers of ions dissolved)
m = mol /kg → 0.257 mol / 0.250kg = 1.03 m
Kf = Cryoscopic constant → 1.86 ºC/m (pure, for water)
0ºC - Tºf = 1.03m . 1.86ºC/m . 2
Tºf = -3.82ºC
Answer:
1. mol/L
2. 0.120 M
Explanation:
1. Molarity is equal to the moles of solute divided by the liters of solution. The units of molarity are mol/L.
2.
Step 1: Given data
- Mass of sodium chloride (solute): 5.25 g
- Volume of solution (V): 750.0 mL = 0.7500 L
Step 2: Calculate the moles of solute (n)
The molar mass of NaCl is 58.44 g/mol.
n = 5.25 g × 1 mol/58.44 g = 0.0898 mol
Step 3: Determine the molarity of the solution
We will use the definition of molarity
M = n/V
M = 0.0898 mol / 0.7500 L = 0.120 M
Answer:
sulfuric acid
Explanation:
a strong acid that soluble in water.
it is water energy :) this is easy