1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Elan Coil [88]
1 year ago
5

PCl5 decomposes to PCl3 and Cl2. If the initial concentration of PCl5 is 0. 200 m and the final concentration is 0. 120 m. What

is the equilibrium constant for the reaction?
Chemistry
1 answer:
lina2011 [118]1 year ago
3 0

PCl5 decomposes to PCl3 and Cl2.At an equilibrium constant is 0.0533.

The equilibrium constant, ok, expresses the connection among merchandise and reactants of a reaction at equilibrium with admire to a selected unit. The quantity values for are taken from experiments measuring equilibrium concentrations. The value of k shows the equilibrium ratio of merchandise to reactants. In an equilibrium mixture each reactants and products co-exist. big k > 1 products are desired k = 1 neither reactants nor merchandise are preferred.

The equilibrium will shift within the reverse path so that the effect of increased strain is nullified. for this reason, with growth in stress, the dissociation of PCl5 is suppressed and the degree of dissociation of PCl5 decreases.

PCl5  ===========> PCl3 +  CL2

0.200                                   0             0    (initial)

0.200-x                                x             x   (at equilibrium)

at equilibrium [PCL5] = 0.120

SO,

0.200 - x = 0.120

x = 0.080 M

Kc = [PCl3] [Cl2] / [PCl5]

    = x*x / (0.200 -x)

     = 0.080 * 0.080 / (0.120)

      = 0.0533

Hence equilibrium constant is  = 0.0533.

Learn more about concentration here:-brainly.com/question/17206790

#SPJ4

You might be interested in
A sample compound contains 5.723g Ag, 0.852g S and 1.695g O. Determine its empirical formula.
Lubov Fominskaja [6]

Answer:

Ag_2SO_4

Explanation:

Formula for the calculation of no. of Mol is as follows:

mol=\frac{mass\ (g)}{molecular\ mass}

Molecular mass of Ag = 107.87 g/mol

Amount of Ag = 5.723 g

mol\ of\ Ag=\frac{5.723\ g}{107.87\ g/mol} =0.05305\ mol

Molecular mass of S = 32 g/mol

Amount of S = 0.852 g

mol\ of\ S=\frac{0.852\ g}{32\ g/mol} =0.02657\ mol

Molecular mass of O = 16 g/mol

Amount of O = 1.695 g

mol\ of\ O=\frac{1.695\ g}{16\ g/mol} =0.10594\ mol

In order to get integer value, divide mol by smallest no.

Therefore, divide by 0.02657

Ag, \frac{0.05305}{0.02657} \approx 2

S, \frac{0.02657}{0.02657} \approx 1

O, \frac{0.10594}{0.02657} \approx 4

Therefore, empirical formula of the compound = Ag_2SO_4

7 0
3 years ago
Read 2 more answers
An atom has 17 protons and 18 neutrons.
Wewaii [24]

Answer:

Cl

Explanation:

cl has mass number 35 and its atomic number is 17 so number of proton =atomic number 17 and number of neutron is =mass number -number of proton =35-17 =18

3 0
3 years ago
How many atoms are in<br> 3Ca(CIO3)2
satela [25.4K]

Answer:

Explanation:

Percent composition by element

Element Symbol # of Atoms

Chlorine Cl 2

Calcium Ca 1

Oxygen O 6

4 0
2 years ago
Which is the most accurate description of compounds?
Alex787 [66]
The answer has to be D
8 0
2 years ago
Read 2 more answers
3Cu + 8HNO = 3Cu(NO3)2 +2NO + 4H2O
AysviL [449]

Taking into account the reaction stoichiometry, 5.2634 grams of Cu(NO₃)₂ are formed when 4.69 grams of HNO₃, assuming an excess of solid copper is present.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

3 Cu+ 8 HNO₃ → 3 Cu(NO₃)₂ + 2 NO + 4 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Cu: 3 moles
  • HNO₃: 8 moles
  • Cu(NO₃)₂: 3 mole
  • NO: 2 moles
  • H₂O: 4 moles

The molar mass of the compounds is:

  • Cu: 63.55 g/mole
  • HNO₃: 63 g/mole
  • Cu(NO₃)₂: 187.55 g/mole
  • NO: 30 g/mole
  • H₂O: 18 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • Cu: 3 moles ×63.55 g/mole= 190.65 grams
  • HNO₃: 8 moles ×63 g/mole= 504 grams
  • Cu(NO₃)₂: 3 moles ×187.55 g/mole= 562.65 grams
  • NO: 2 moles ×30 g/mole= 60 grams
  • H₂O: 4 moles ×18 g/mole= 72 grams

<h3>Mass of Cu(NO₃)₂ produced</h3>

The following rule of three can be applied: if by reaction stoichiometry 504 grams of HNO₃ form 562.65 grams of Cu(NO₃)₂, 4.69 grams of HNO₃ form how much mass of Cu(NO₃)₂?

mass of Cu(NO_{3} )_{2} =\frac{4.69 grams of HNO_{3}  x562.65 grams of Cu(NO_{3} )_{2} }{504 grams of HNO_{3} }

<u><em>mass of Cu(NO₃)₂=  5.2634 grams</em></u>

Then, 5.2634 grams of Cu(NO₃)₂ are formed when 4.69 grams of HNO₃, assuming an excess of solid copper is present.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

7 0
2 years ago
Other questions:
  • What do all four animals have in common? cat worm spider crab
    8·1 answer
  • What is the term for the process that occurs when k+ and br- ions are pulled into solution?
    9·2 answers
  • Why did most scientists reject Wegner's theory for nearly a half century?
    9·1 answer
  • List three organelles found in cells and describe their functions.
    13·2 answers
  • You wish to make a 0.299 M hydroiodic acid solution from a stock solution of 6.00 M hydroiodic acid. How much concentrated acid
    7·1 answer
  • When molybdate (MoO3) and Zinc (Zn) are heated together they react in this equation:
    7·1 answer
  • Calculate the amount of formula units in 2.10 moles of MgCl₂
    5·1 answer
  • The density of a sample of gasoline is 0.70 g/cm3. What is the mass of 1 liter of this gasoline?
    11·1 answer
  • How much heat is absorbed in the complete reaction of 3.00 grams of SiO2 with excess carbon in the reaction SiO2(g) + 3C(s) → Si
    7·1 answer
  • Gold is formed in pure state in nature but not iron,why?​
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!