Thursday

Prove the Congruent Tangent Segments Theorem.Given: BA and BC are tangent to o O at A and C.respectivelyProve: BABCStatementsRea

motikmotik

A line crossing the circle at point A and passing through its center O is perpendicular to a line tangent to the circle at point A.

Therefore, segment AB is perpendicular to OA. And segment BC is perpendicular to OC:

8 0

1 year ago

Hi im stuck on this problem, is anybody able explain to me how to do it? This is Two-Variable Substitution

Free_Kalibri [48]

The answer is a. the first step is to divide the whole bottom equation by -1 because x can’t be negative. you then plug in y + 9 into the first equation to solve. so the equation would be (y + 9) + y = 11. you do this because in substitution you plug in one of the equations into the other equation. you then get 2y + 9= 11. you would next subtract 9 to both sides which leaves you with 2y= 2, divide by both sides, y = 1. you then plug the why value into the first equation to figure out the value for x. so it would be x + 1 = 11, subtract 1, x equals 10.

sorry this was hard to explain! hope this helps!

6 0

4 years ago

Double and half angle identities?

Maru [420]

Answer:

Option 4

Step-by-step explanation:

Given:

Sinθ = $\frac{15}{17}$

Since, cos2θ = 1 - 2sin²θ

cos2θ = $1-2(\frac{15}{17})^2$

cos2θ = 1 - $\frac{450}{289}$

cos2θ = $\frac{289-450}{289}$

cos2θ = $-\frac{161}{289}$

Therefore, Option 4 will be the answer.

8 0

3 years ago

Which equation does the graph below represent?

Gnom [1K]

I dont see a graph cant help you

6 0

3 years ago

Question: An airport deli sells turkey, ham, and roast beef sandwiches. A customer can choose between turkey,

Dmitry_Shevchenko [17]

Answer:

$\displaystyle \frac{1}{12}$ .

Step-by-step explanation:

Ginger selects the ingredients randomly. Therefore, the choices she makes would be independent. In other words, her choice of cheese (and mayonnaise) won't depend on what she chose for meat. Therefore:

$\begin{aligned}& P(\text{(roast beef) and (cheese) and (no mayonnaise)}) \\ &= P(\text{roast beef})\cdot P(\text{cheese}) \cdot P(\text{no mayonnaise})\end{aligned}$ .

It is worth noting that this equality would not be valid if the choices are not independent. For example, if Ginger is more likely to choose mayonnaise after choosing cheese, then $P(\text{(roast beef) and (cheese) and (no mayonnaise)})$ and $P(\text{roast beef})\cdot P(\text{cheese}) \cdot P(\text{no mayonnaise})$ would likely be different.

What is the probabilities that Ginger would select roast beef for the sandwich? The question states that Ginger is "equally likely" to select each of turkey, ham, and roast beef. In other words:

$P(\text{roast beef})= P(\text{turkey}) = P(\text{ham})$ .

At the same time, Ginger has to choose exactly one of these options. She can't choose no meat of more than one options at a time. Therefore:

$P(\text{roast beef})+ P(\text{turkey}) + P(\text{ham}) = 1$ .

Combine these two equations to conclude that:

$\displaystyle P(\text{roast beef}) = \frac{1}{3}$ .

Similarly, Ginger has to choose between cheese or no cheese, and mayonnaise or no mayonnaise. Therefore:

$\displaystyle P(\text{cheese}) = \frac{1}{2}$ .
$\displaystyle P(\text{mayonnaise}) = \frac{1}{2}$ .

Back to the probability for roast beef, cheese, and no mayonnaise:

$\begin{aligned}& P(\text{(roast beef) and (cheese) and (no mayonnaise)}) \\ &= P(\text{roast beef})\cdot P(\text{cheese}) \cdot P(\text{no mayonnaise}) \\ &= \frac{1}{3} \times \frac{1}{2} \times \frac{1}{2} \\ &= \frac{1}{12}\end{aligned}$ .

8 0

4 years ago