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irina1246 [14]
1 year ago
10

On which of saturn’s moons did the cassini-huygens probe land in 2004, providing our first view of the varied and active surface

?
Physics
1 answer:
yawa3891 [41]1 year ago
4 0

On Titan, the largest moon of of Saturn did the Cassini-Huygens probe land in 2004.

To find the answer, we have to know more about the Cassini-Huygens Mission.

<h3>What is Cassini-Huygens mission?</h3>
  • Before arriving at its final destination of Saturn in 2004 and beginning a series of flybys of Saturn's moons, the spacecraft contributed to studies of Jupiter for six months in 2000.
  • In the same year, it launched the Huygens probe to explore Titan's atmosphere and surface makeup on Saturn's moon.
  • During its second extended mission, Cassini sailed between the rings, entered the planet's atmosphere, and obtained the first measurements of a whole seasonal period for Saturn and its moons.

Thus, we can conclude that, on Titan, the largest moon of of Saturn did the Cassini-Huygens probe land in 2004.

Learn more about the Cassini-Huygens mission here:

brainly.com/question/27907891

#SPJ4

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Which of the following observations indicates that an object is falling at terminal velocity?
vitfil [10]

Answer:  D

Explanation:

When an object falls gravity is pulling down on it and is picking up speed, but as it gains speed air resistance becomes a faster. Air resistance increases with speed. And that force keeps it from accelerating eventually the object will pick up speed such that the force due to air resistance will keep it from getting any more speed at that point force due to air resistance is equal to its weight (mg) and the net force is equal to zero so it won’t accelerate any more at that point it is said to be moving in terminal velocity.

When an object has reached terminal velocity, it will have a constant velocity

5 0
3 years ago
Consider a horse pulling a buggy. Is the
Degger [83]

Yes, it's true.

But 2nd Newton Law always come to play when the horse is to move forward because obviously the forces interact antagonistically and mass has to be accounted for.

That's what I think. Hope it's right, all the best.

8 0
3 years ago
Mass is the amount of matter in an object what describes the amount of space the object takes up?
saveliy_v [14]
C volume because the volume take up the Mater and space around it thing
6 0
1 year ago
A 4.9-MeV (kinetic energy) proton enters a 0.28-T field, in a plane perpendicular to the field. Part APart complete What is the
BartSMP [9]

Answer:

r=1.14m

Explanation:

\theta is the angle between the velocity and the magnetic field. So, the magnetic force on the proton is:

F_m=qvBsen\theta\\F_m=qvBsen(90^\circ)\\F_m=qvB

A charged particle describes a semicircle in a uniform magnetic field. Therefore, applying Newton's second law to uniform circular motion:

F_m=F_c\\qvB=F_c(1)

F_c is the centripetal force and is defined as:

F_c=m\frac{v^2}{r}

Here v is the proton's speed and r is the radius of the circular motion. Replacing this in (1) and solving for r:

qvB=\frac{mv^2}{r}\\r=\frac{mv^2}{qvB}\\r=\frac{mv}{qB}

Recall that 1 J is equal to 6.242*10^{12}MeV, so:

4.9MeV*\frac{1J}{6.242*10^{12}MeV}=7.85*10^{-13}J

We can calculate v from the kinetic energy of the proton:

K=\frac{mv^2}{2}\\\\v=\sqrt{\frac{2K}{m}}\\v=\sqrt{\frac{2(7.85*10^{-13}J)}{1.67*10^{-27}kg}}\\v=3.06*10^{7}\frac{m}{s}

Finally, we calculate the radius of the proton path:

r=\frac{mv}{qB}\\r=\frac{1.67*10^{-27}kg(3.06*10^{7}\frac{m}{s})}{1.6*10^{-19}C(0.28T)}\\r=1.14m

8 0
3 years ago
IS
jarptica [38.1K]

Answer:

5.03

Explanation:

trust me

7 0
2 years ago
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