Evaporation and boiling.
Evaporation refers to only the surface level turning it into a gas and the vaporization pressure of the liquid remains low.
When a substance boils it’s pressure is high and the surface evaporated along with the rest of the liquid at an equal rate. A sign of boiling is the presence of bubbles, which occur only in the process of boiling and not in evaporation.
A example of boiling is heating water up to the point until you see steam and bubbles.
A example of evaporation is the melting of an ice cube.
Hope this helps
Answer:
Vr = 3.24m/s
The boat is going 3.24m/s relative to the bank of the river.
Explanation:
The relative speed of the boat to the bank Vr is the resultant of speed of boat relative to the water Vb and the speed of boat as a result of the water current or wind Vw
Vr = √(Vb^2 + Vw^2) .....1
Given;
Vb = 2.6m/s
Vw = distance downstream/time = 690m/355s
Vw = 1.94m/s
From equation 1 above; substituting the values
Vr = √(2.6^2 + 1.94^2)
Vr = 3.24m/s
The boat is going 3.24m/s relative to the bank of the river.
Answer:
Decreasing the use of fossil fuels will improve the wellbeing of animals (and people, for that matter). Burning fossil fuels like coal and using oil and other limited resources has polluted the biosphere, and this has had an adverse impact on many animals. If we were to limit this, it would no doubt improve their situation and make them less likely to extinction.
The ball is going Zero miles right before the player kicks it.
Answer:
The bond energy of F–F = 429 kJ/mol
Explanation:
Given:
The bond energy of H–H = 432 kJ/mol
The bond energy of H–F = 565 kJ/mol
The bond energy of F–F = ?
Given that the standard enthalpy of the reaction:
<u>H₂ (g) + F₂ (g) ⇒ 2HF (g)</u>
ΔH = –269 kJ/mol
So,
<u>ΔH = Bond energy of reactants - Bond energy of products.</u>
<u>–269 kJ/mol = [1. (H–H) + 1. (F–F)] - [2. (H–F)]</u>
Applying the values as:
–269 kJ/mol = [1. (432 kJ/mol) + 1. (F–F)] - [2. (565 kJ/mol)]
Solving for , The bond energy of F–F , we get:
<u>The bond energy of F–F = 429 kJ/mol</u>
