Answer:
1) It expresses the rate (top speed) at which it can move with time.
2) P = 20 W
3) h = 18 km
Explanation:
1) Power is the rate of transfer of energy.
⇒ Power = ![\frac{Energy(or workdone)}{Time}](https://tex.z-dn.net/?f=%5Cfrac%7BEnergy%28or%20workdone%29%7D%7BTime%7D)
i.e P = ![\frac{E}{t}](https://tex.z-dn.net/?f=%5Cfrac%7BE%7D%7Bt%7D)
Thus a car's engine power is 44000W implies that the engine of the car can propel the car at this rate. This expresses the rate (top speed) at which it can move with time.
2) m = 400g = 0.4 kg
t = 20 s
h = 100m
g = 10 m/![s^{2}](https://tex.z-dn.net/?f=s%5E%7B2%7D)
P = ![\frac{mgh}{t}](https://tex.z-dn.net/?f=%5Cfrac%7Bmgh%7D%7Bt%7D)
= ![\frac{0.4*10*100}{20}](https://tex.z-dn.net/?f=%5Cfrac%7B0.4%2A10%2A100%7D%7B20%7D)
= ![\frac{400}{20}](https://tex.z-dn.net/?f=%5Cfrac%7B400%7D%7B20%7D)
P = 20 W
3) u = 600 m/s
g = 10 m/![s^{2}](https://tex.z-dn.net/?f=s%5E%7B2%7D)
From the third equation of free fall,
=
- 2gh
V is the final velocity, U is the initial velocity, h is the height.
0 =
- 2 x 10 x h
0 = 360000 - 20h
20h = 360000
h = ![\frac{360000}{20}](https://tex.z-dn.net/?f=%5Cfrac%7B360000%7D%7B20%7D)
= 18000
h = 18 km
The maximum height of the bullet would be 18 km.
if one of the charge is doubled, the electric potential energy would be doubled too
Answer:
Q₂ = 5833.33 J
Explanation:
First we need to find the energy supplied to the heat engine. The formula for the efficiency of the heat engine is given as:
η = W/Q₁
where,
η = efficiency of engine = 30% = 0.3
W = Work done by engine = 2500 J
Q₁ = Heat supplied to the engine = ?
Therefore,
0.3 = 2500 J/Q₁
Q₁ = 2500 J/0.3
Q₁ = 8333.33 J
Now, we find the heat discharged to lower temperature reservoir by using the formula of work:
W = Q₁ - Q₂
Q₂ = Q₁ - W
where,
Q₂ = Heat discharged to the lower temperature reservoir = ?
Therefore,
Q₂ = 8333.33 J - 2500 J
<u>Q₂ = 5833.33 J</u>