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Alina [70]
3 years ago
7

It can take some of those large , industrial vehicles up to ____ feet to stop when traveling only 60 MPH, and therefore , you sh

oukd be mindful to not be jn the traffic right in front of them
A. 100 feet
B. 200 feet
C. 335 feet
D. 425 feet
Physics
1 answer:
kherson [118]3 years ago
4 0

Answer:

a 200 feet, and trains go  a whole mile even after hitting the brakes

Explanation:

You might be interested in
A light spring of constant 176 N/m rests vertically on the bottom of a large beaker of water.
irakobra [83]

Answer:

14.0 cm

Explanation:

Draw a free body diagram of the block.  There are three forces: weight force mg pulling down, elastic force k∆L pulling down, and buoyancy ρVg pushing up.

Sum of forces in the y direction:

∑F = ma

ρVg − mg − k∆L = 0

(1000 kg/m³) (4.63 kg / 648 kg/m³) (9.8 m/s²) − (4.63 kg) (9.8 m/s²) − (176 N/m) ∆L = 0

∆L = 0.140 m

∆L = 14.0 cm

8 0
3 years ago
A bar magnet is dropped from above and falls through the loop of wire. The north pole of the bar magnet points downward towards
8_murik_8 [283]

Answer:

<em>b. The current in the loop always flows in a counterclockwise direction.</em>

<em></em>

Explanation:

When a magnet falls through a loop of wire, it induces an induced current on the loop of wire. This induced current is due to the motion of the magnet through the loop, which cause a change in the flux linkage of the magnet. According to Lenz law, the induced current acts in such a way as to repel the force or action that produces it. For this magnet, the only opposition possible is to stop its fall by inducing a like pole on the wire loop to repel its motion down. An induced current that flows counterclockwise in the wire loop has a polarity that is equivalent to a north pole on a magnet, and this will try to repel the motion of the magnet through the coil. Also, when the magnet goes pass the wire loop, this induced north pole will try to attract the south end of the magnet, all in a bid to stop its motion downwards.

3 0
3 years ago
What is the electric field strength between two parallel plates 5cm apart with a potential difference of 25V across them?
Butoxors [25]

Use the following formula for the electric field strength between two parallel plates:

E = V/d

where,

V: potential difference = 25V

d: distance between plates = 5 cm = 0.05 m

Replace the previous values of the parameters into the formula for E:

E=\frac{25V}{0.05m}=500\frac{V}{m}

Hence, the electric field strength is 500V/m

5 0
1 year ago
I NEED HELP WITH THE LAST QUESTION PLS HELP!! (The one below 8)
maksim [4K]

Answer:

I. 6 cells .

II. Series connection.

Explanation:

I. Determination of the number of cells needed.

From the question given above,

Total voltage (V) = 9 V

1.5 V = 1 cell

Number of cells needed =?

The number of cells needed to make the 9V battery can be obtained as follow:

1.5 V = 1 cell

Therefore,

9 V = 9 V × 1 cell / 1.5 V

9 V = 6 cells

Thus, 6 cells of 1.5 V each is needed

II. Determination of the connection line

Total voltage (Vₜ) = 9 V

Cell 1 (V₁) = 1.5 V

Cell 2 (V₂) = 1.5 V

Cell 3 (V₃) = 1.5 V

Cell 4 (V₄) = 1.5 V

Cell 5 (V₅) = 1.5 V

Cell 6(V₆ ) = 1.5 V

For parrall connection:

Vₜ = V₁ = V₂ = V₃ = V₄ = V₅ = V₆

9 V = 1.5 V =... = 1.5 V

For series connection:

Vₜ = V₁ + V₂ + V₃ + V₄ + V₅ + V₆

9 = 1.5 + 1.5 + 1.5 + 1.5 + 1.5 + 1.5

9 V = 9 V

From the illustration above, we can see that series connection of each cells will give a total volt of 9 V unlike the parallel connection which resulted to 1.5 V.

Therfore, the cells should be arranged in series connection

8 0
2 years ago
Which law can be used to calculate the number of moles of a contained gas?
mafiozo [28]
It is the Ideal Gas Law.

Recall the formula for the law,  PV = nRT,

n in the formula is the number of moles of the gas.

C.
3 0
3 years ago
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