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-BARSIC- [3]
3 years ago
3

The variables for this experiment include mass, volume and the materials in the various balls, as well as their densities. In Pa

rt III, you will be investigating the questionable baseball. Use the drop-down menus to complete the sentences and identify the independent and dependent variables. In Part III, the independent variable, the one that is intentionally manipulated, is . In Part III, the dependent variable, the one that you measure the response in, is .
Chemistry
2 answers:
cricket20 [7]3 years ago
8 0

Answer:

In Part III, the independent variable, the one that is intentionally manipulated, is material.              In Part III, the dependent variable, the one that you measure the response in, is

✔ density

Explanation:

Sidana [21]3 years ago
6 0

Explanation:

A variable is any factor, trait, or condition that can exist in differing amounts or types. An experiment usually has three kinds of variables: independent, dependent, and controlled. The independent variable is the one that is changed by the scientist.

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___________ polymers can be produced in large quantities at low cost. please. thank you.
MA_775_DIABLO [31]

Answer:

Plastic polymers

Explanation:

Plastic polymers are usually made up of synthetic and semi-synthetic polymers such as polyethylene, polystyrene etc.

Plastic polymers have a unique property called malleability. Malleability is the ability of a substance to be moulded into different sizes and shapes.

When hear is applied plastics gets soft and can be molded into different forms and then it becomes hardened after exposure to air(dried).

The plastic polymers are usually very cheap to produce in large quantities which is why it is very common in industries.

5 0
3 years ago
How are proteins, carbohydrates, and fats related to the discipline of chemistry?
natali 33 [55]
*food science* 
When you consume proteins, carbs, and fats they are chemically changed into energy. 
3 0
3 years ago
Read 2 more answers
A balloon is floating around outside your window. The temperature outside is 21 ∘C , and the air pressure is 0.700 atm . Your ne
Andreyy89

Answer:

V=162L

Explanation:

Hello,

In this case, we can compute the required volume by using the ideal gas equation as shown below:

PV=nRT

Thus, solving for the volume and considering absolute temperature (in Kelvins), we obtain:

V=\frac{nRT}{P}= \frac{4.70mol*0.082\frac{atm*L}{mol*K}*(21+273)K}{0.700atm} \\\\V=162L

Best regards.

4 0
3 years ago
A reaction produces 74.10 g Ca(OH)2 after 56.08 g CaO is added to 36.04 g H2O. How should the difference in the masses of reacta
melomori [17]
Cao +  H2O  ---->Ca(OH)2
Calculate   the  number  of  each   reactant  and  the  moles  of  the  product
that  is
moles = mass/molar mass
The  moles  of  CaO=  56.08g/  56.08g/mol(molar  mass  of  Cao)=  1mole
the  moles  of  water=  36.04 g/18  g/mol=  2.002moles
The   moles  of Ca (OH)2=74.10g/74.093g/mol= 1mole

 The  mass  of differences  of  reactant  and  product  can   be  therefore 
 explained  as 
 1  mole   of  Cao  reacted  completely   with   1  mole   H2O  to  produce  1 mole  of  Ca(OH)2. The  mass  of  water   was  in  excess  while  that  of  CaO  was  limited

3 0
3 years ago
Please help with this question ;/
aev [14]
The link above is a hacker
8 0
3 years ago
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