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-BARSIC- [3]
3 years ago
3

The variables for this experiment include mass, volume and the materials in the various balls, as well as their densities. In Pa

rt III, you will be investigating the questionable baseball. Use the drop-down menus to complete the sentences and identify the independent and dependent variables. In Part III, the independent variable, the one that is intentionally manipulated, is . In Part III, the dependent variable, the one that you measure the response in, is .
Chemistry
2 answers:
cricket20 [7]3 years ago
8 0

Answer:

In Part III, the independent variable, the one that is intentionally manipulated, is material.              In Part III, the dependent variable, the one that you measure the response in, is

✔ density

Explanation:

Sidana [21]3 years ago
6 0

Explanation:

A variable is any factor, trait, or condition that can exist in differing amounts or types. An experiment usually has three kinds of variables: independent, dependent, and controlled. The independent variable is the one that is changed by the scientist.

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What is the mass of 1.7 × 1023 atoms of zinc
fiasKO [112]

We are given with a compound, Zinc (Zn) having a 1.7 x 10 ^23 atoms. We are tasked to solve for it's corresponding mass in g. We need to find first the molecular weight of Zinc, that is

Zn= 65.38 g/mol

Not that 1 mol=6.022x10^{23} atoms, hence,

1.7 x 10 ^23 atoms x 1 mol/6.022x10^{23} atoms x65.38 g/ 1mol

=18.456 g of Zn

 

Therefore, the mass of Zinc 18.456 g

3 0
3 years ago
The chemical equation below shows the combustion of methane (CH4).
pishuonlain [190]
According to the chemical equation, the reaction ratio between O2 and CO2 is 2:1, which mean for every 2 moles of O2 reacted there is 1 mole of CO2 formed. 

Use the molar mass and mass of O2 to find out the moles of O2: moles of O2 = mass of O2/molar mass of O2 = 8.94g/32.00g/mol = 0.2794 mole.  Therefore, the moles of CO2 that formed is 0.2794moles/2 = 0.1397 mole

Use the moles and molar mass CO2 to find out the mass of CO2:
Mass of CO2 = moles of CO2 * molar mass of CO2 = 0.1397 mole * .44.01g/mole = 6.15 g.

So the answer is B 6.15g.
3 0
3 years ago
Read 2 more answers
A solution is prepared by dissolving 4.40 g of KSCN in enough water to make 200 mL of solution. What is the concentration of the
attashe74 [19]
First find the number of moles of KSCN is in 4.40g of KSCN 1. Number of moles = mass given (4.40g) / molecular weight(MW) (KSCN) - to calculate MW, look for each element in the periodic table and add their atomic weight 2. Convert 200mL to liters 3. Concentration = number of moles/ volume in liters from (#2)
4 0
3 years ago
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Calculate the volume, in ml. of the 1.0 m naoh stock solution needed to prepare 250 ml of 0.1 molar naoh.
Aneli [31]
By using the following formula we can calculate the volume;
C₁V₁ = C₂V₂
C₁ = concentration of starting solution = 1.0m
V₁ = volume of starting solution that is needed to make the dilution = ?
C₂ = Desired concentration of final solution = 0.1m
V₂ = desired volume of final solution = 250ml
Now putting the values in the formula;
1 x V₁ = 0.1 x 250
V₁ = 25ml
Thus, the answer is 25ml.

8 0
3 years ago
How many moles of naoh will react with 13.5 moles of k3po4
Alona [7]

Answer: 40.5 mol

Explanation:

Since this is a double replacement reaction, the unbalanced equation is something like follows:

\text{K}_{3}\text{PO}_{4}+\text{NaOH} \longrightarrow \text{KOH}+\text{Na}_{3}\text{PO}_{4}

Balancing this equation,

\text{K}_{3}\text{PO}_{4}+3\text{NaOH} \longrightarrow 3\text{KOH}+\text{Na}_{3}\text{PO}_{4}

From this equation, we can conclude that for every 3 moles of sodium hydroxide consumed, 1 mole of potassium phosphate is consumed.

This means the answer is 13.5(3)=<u>40.5 mol</u>

8 0
2 years ago
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