Answer:
4 m, 1.71 m and 6.29 m
Explanation:
Let L = 8 m be the distance between the two speakers. Let x be the distance from speaker A of constructive interference. The distance to speaker B from the point of constructive interference is thus x₁ = L - x.
There is constructive interference when the distance x₁ - x = nλ where n = is an integer and λ = wavelength L - x
x₁ - x = nλ
L - x - x = nλ
L - 2x = nλ
x = (L - nλ)/2 = (L - nv/f)/2. where v = speed of wave = 343 m/s and f = frequency = 75 Hz
The distance from A where constructive interference would occur starts from when
n = 0
x₂ = (L - nv/f)/2 = (8 - 0 × 343/75)/2 = (8 - 0)/2 = 8/2 = 4 m
n = 1
x₃ = (L - nv/f)/2 = (8 - 1 × 343/75)/2 = (8 - 4.57)/2 = 3.43/2 = 1.71 m
when n = 2
x₄ = (L - nv/f)/2 = (8 - 2 × 343/75)/2 = (8 - 9.14)/2 = -1.15/2 = -0.57 m
So the value at n = 2 is not included.
The third point occurs at x₅ = L - x₃ where x₃ = 1.71 m is the distance away from point B where constructive interference also occurs. (since it is symmetrical about the point x₂ = 4 m
x₅ = L - x₃ = 8 - 1.71 = 6.29 m
Gravity or gravitation, is a natural phenomenon by which all things with mass or energy—including planets, stars, galaxies, and even light—are brought toward (or gravitate toward) one another. - google
Like-charged bodies will repel each other. When they're brought
closer together, they'll repel each other with even more force.
Answer:
d=1.49×1011m
Explanation:
Velocity is defined as the rate of travel, and can be found using the distance formula.
velocity=distancetime
Rearranging this formula we can solve for distance given velocity and time of travel.
d=vt
We are given velocity and time, and so can solve for distance, but if we plug in the values given;
d=(3.00×108m/s)(8.3minutes)
We can see that the units do not match up. Since seconds are the SI unit for time, we will need to convert 8.3 minutes to seconds.
t=(8.3minutes)(60seconds/minute)=(498s)
Now our units work out and we can solve for distance.
= 15.85
Answer:
Reflection of sound waves also leads to echoes. Echoes are different than reverberations. Echoes occur when a reflected sound wave reaches the ear more than 0.1 seconds after the original sound wave was heard. ... Reflection of sound waves off of curved surfaces leads to a more interesting phenomenon.
