This is problem of free falling
objects, which can be solved using the formula:
V = sqrt(2gy)
Where v is the velocity upon
impact
G is the acceleration due to
gravity ( 9.81 m/s2)
Y is the height
Since Venessa is 3.5 m
Y = 30 -3.5 = 26.5 m
V = sqrt(2 (9.81 m/s2) ( 26.5
m))
<span>V = 22.8 m/s</span>
Answer:
= 4.86 s
= 1.98 s
Explanation:
<u><em>Given:</em></u>
Length = l = 1 m
Acceleration due to gravity of moon = 
= 1.67 m/s²
Acceleration due to gravity of Earth = 
= 10 m/s²
<u><em>Required:</em></u>
Time period = T = ?
<u><em>Formula:</em></u>
T = 2π 
<u><em>Solution:</em></u>
<u>For moon</u>
<em>Putting the givens,</em>
T = 2(3.14) 
T = 6.3 
T = 6.3 × 0.77
T = 4.86 sec
<u>For Earth,</u>
<em>Putting the givens</em>
T = 2π 
T = 2(3.14) 
T = 6.3 × 0.32
T = 1.98 sec
Answer:
Speed of the helium after collision = 246 m/s
Explanation:
Given that
Mass of helium ,m₁ = 4 u
u₁=598 m/s
Mass of oxygen ,m₂ = 32 u
u₂ = 401 m/s
v₂ =445 m/s
Given that initially both are moving in the same direction and lets take they are moving in the right direction.
Speed of the helium after collision = v₁
There is no any external force on the masses that is why the linear momentum will be conserve.
Initial linear momentum = Final linear momentum
P = m v
m₁u₁+m₂u₂ = m₁v₁+m₂v₂
598 x 4 + 32 x 401 = 4 x v₁+ 32 x 445
v₁ = 246 m/s
Speed of the helium after collision = 246 m/s
Answer:
The last statement is false.
Explanation:
Photons (Electromagnetic radiation) are released when electrons drop from a higher energy lever to a lower energy level. Therefore the opposite insinuated by the last statement is wrong.
The Earth's gravity keeps the Moon orbiting us. It keeps changing the direction of the Moon's velocity. This means gravity makes the Moon accelerate all the time, even though its speed remains constant.
