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KATRIN_1 [288]
2 years ago
12

Pls answer it ASAP I need it today

Physics
1 answer:
Lapatulllka [165]2 years ago
4 0
Detergents are special, powerful cleansers that can break up dirt, oils, and grease in clothing or on dishes.

Cleaning solvents are used to remove oil, grease, solder flux, and other contaminants.

Acid cleaners are generally used to remove mineral deposits and are useful for descaling dishwashers or removing rust from restroom facilities.

Abrasive uses
* Buffing.
* Honing.
* Drilling.
* Grinding.
* Sanding.
* Polishing.
* Cutting.
* Sharpening.
You might be interested in
Calculate the acceleration of a bus that goes
Svet_ta [14]

The acceleration of the bus is 1.11 meters per second square to the direction of motion

Explanation:

Acceleration is the rate of change of velocity

The formula of the acceleration is a=\frac{v_{2}-v_{1}}{t} , where

  • v_{1} is the initial velocity
  • v_{2} is the final velocity
  • t is the time

A bus that goes  from 10 km/h to a speed of 50 km/h in 10 seconds

→ v_{1} = 10 km/h

→ v_{2} = 50 km/h

→ t = 10 seconds

Change the unite of the time from seconds to hour

→ 1 hour = 60 × 60 = 3600 seconds

→ 10 seconds = \frac{10}{3600}=\frac{1}{360} hour

Substitute these values in the formula of the acceleration above

→ a=\frac{50-10}{\frac{1}{360}}

→ a = 14400 km/h²

To change the unit of acceleration to meter per second change the

  kilometer to meter and the hour to seconds

→ 1 km = 1000 m

→ 1 hour = 3600 seconds

→ a=\frac{14400*1000}{(3600)^{2}}=\frac{10}{9}

→ a = 1.11 m/sec².

The acceleration of the bus is 1.11 meters per second square to the direction of motion

Learn more:

You can learn more about the acceleration in brainly.com/question/6323625

#LearnwithBrainly

4 0
4 years ago
Imagine that you are going to visit your friend. Before you get there, you decide to stop at the variety store. If you walk 200
SashulF [63]

Answer:

400m

Explanation:

Brainliest? :))

Let your initial displacement from your home to the store be

Dd

>

1 and your displacement from the store to your friend’s house

be Dd

>

2.

Given: Dd

>

1 = 200 m [N]; Dd

>

2 = 600 m [S]

Required: Dd

>

T

Analysis: Dd

>

T 5 Dd

>

1 1 Dd

>

2

Solution: Figure 6 shows the given vectors, with the tip of Dd

>

1

joined to the tail of Dd

>

2. The resultant vector Dd

>

T is drawn in red,

from the tail of Dd

>

1 to the tip of Dd

>

2. The direction of Dd

>

T is [S].

Dd

>

T measures 4 cm in length in Figure 6, so using the scale of

1 cm : 100 m, the actual magnitude of Dd

>

T is 400 m.

Statement: Relative to your starting point at your home, your

total displacement is 400 m [S].

6 0
2 years ago
A boy weighs 400N. what is his mass?
Basile [38]

≈40.8kg


this is to take up space


m

=

W

g


=

400

N

9.8

m/s

2


≈

40.8

kg

m

=

W

g


=

400

N

9.8

m/s

2


≈

40.8

kg

m

=

W

g


=

400

N

9.8

m/s

2


≈

40.8

kg

m

=

W

g


=

400

N

9.8

m/s

2


≈

40.8

kg

m

=

W

g


=

400

N

9.8

m/s

2


≈

40.8

kg

m

=

W

g


=

400

N

9.8

m/s

2


≈

40.8

kg

m

=

W

g


=

400

N

9.8

m/s

2


≈

40.8

kg

m

=

W

g


=

400

N

9.8

m/s

2


≈

40.8

kg

m

=

W

g


=

400

N

9.8

m/s

2


≈

40.8

kg

m

=

W

g


=

400

N

9.8

m/s

2


≈

40.8

kg

4 0
3 years ago
Read 2 more answers
A bucket of water of mass 14.0 kg is suspended by a rope wrapped around a windlass, that is a solid cylinder with diameter 0.260
ruslelena [56]

Answer:

The tension in the rope is 41.38 N.

Explanation:

Given that,

Mass of bucket of water = 14.0 kg

Diameter of cylinder = 0.260 m

Mass of cylinder = 12.1 kg

Distance = 10.7 m

Suppose we need to find that,

What is the tension in the rope while the bucket is falling

We need to calculate the acceleration

Using relation of torque

\tau=F\times r

I\times\alpha=F\times r

Where, I = moment of inertia

\alpha = angular acceleration

\dfrac{Mr^2}{2}\times\dfrac{a}{r}=F\times r

F=\dfrac{M}{2}a...(I)

Here, F = tension

The force is

F=m(g-a)...(II)

Where, F = tension

a = acceleration

From equation (I) and (II)

\dfrac{M}{2}a=m(g-a)

a=\dfrac{g}{1+\dfrac{M}{2m}}

Put the value into the formula

a=\dfrac{9.8}{1+\dfrac{12.1}{2\times14.0}}

a=6.84\ m/s^2

We need to calculate the tension in the rope

Using equation (I)

F=\dfrac{M}{2}a

Put the value into the formula

F=\dfrac{12.1}{2}\times6.84

F=41.38\ N

Hence, The tension in the rope is 41.38 N.

6 0
3 years ago
Một người đi đều với vận tốc 1,5 m/s, muốn đi quãng đường dài 1,5 km thì người
andrezito [222]
T=s/v=>t=1500/1,5=1000s
1,5km=1500m
6 0
2 years ago
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