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skad [1K]
3 years ago
15

According to observations, the overall chemical composition of our solar system and other similar star systems is approximately

(a) 98% hydrogen and helium, 2% all other elements combined; (b) 98% ice, 2% metal and rock; (c) 100% hydrogen and helium.
Chemistry
1 answer:
jonny [76]3 years ago
3 0

Answer:A

Explanation:

The solar system consist of the sun, the planets, stars and other objects. The chemical composition of the Sun consist mainly of Hydrogen and helium.

The sun is the largest object in the Solar system, it comprises nearly all the matter in the Solar System, Also the largest planet after the Sun are Jupiter and Saturn are giant planets forming almost the remaining matter of the solar system.

Like the Sun, the mass of Jupiter and Saturn are composed of roughly 98% hydrogen and helium with 2% of all the other elements combined.

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A 0.98 M solution of calcium chloride with a volume of 0.25 L is diluted to form a 0.74 M solution. What is the new volume of th
tankabanditka [31]

The new volume of the dilute solution is 0.33 L.

<u>Explanation:</u>

Using the law of Volumetric analysis, we can find the volume of the dilute solution from the stock solution or the concentrated solution of Calcium Chloride.

V1M1 = V2M2

V1 be the volume of the stock solution = 0.25 L

M1 being the molarity of the stock solution = 0.98 M

V2 be the volume of the dilute solution = ?

M2 being the molarity of the dilute solution = 0.74 M

We have to rearrange the above equation to find V2 as,

V2 = $\frac{V1M1}{M2}

Now plugin the values as,

V2 = $\frac{0.25 L \times 0.98 M }{0.74 M}

   = 0.33 L

So the new volume of the dilute solution is 0.33 L.

3 0
3 years ago
How many grams of sugar must be dissolved in 150 ML of water to make a solution that has a concern traction of .6 g/ml
grandymaker [24]

Hey there!:

Density = 0.6 g/mL

Volume = 150 mL

Mass = ?

therefore:

D = m / V

0.6 = m / 150

m = 0.6 x 150

m = 90.0 g of sugar

Hope this helps!

5 0
3 years ago
A compound is analyzed and found to contain 22.10%Al, 25.40%P, and 52.50%O. What is the empirical formula of the compound?
Whitepunk [10]

Let the total mass of compound is 100g

The mass of each element will be

Al = 22.10 g

P = 25.40 g

O = 52.50 g

In order to determine the molecular formula we will calculate the molar ratio of the given elements

Atomic weight of Al : 27 g/ mol

Atomic weight of P : 3 1g /mol

Atomic weight of O : 16 g /mol

Moles of Al = mass / atomic mass = 22.10 / 27 = 0.819

Moles of P = mass / atomic mass = 25.40/ 31 = 0.819

Moles of O = mass / atomic mass = 52.50/ 16 = 3.28

Now we will divide the moles of each element with the lowest moles obtained to obtain a whole number ratio of moles of each element present

moles of Al = 0.819 / 0.819 = 1

moles of P = 0.819 / 0.819 = 1

moles of O = 3.28 / 0.819 =  4

So the empirical formula will be  : AlPO4

8 0
3 years ago
Given: 2H2O2 → 2H2O + O2 structure of H2O2: H–O–O–H Bond Bond Energy (kJ/mol) O–H 459 O=O 494 O–O 142 Based on the given bond en
ICE Princess25 [194]

Answer:

B. - 210 kJ

Explanation:

<em>∵ ΔHrxn = ∑(bond energies)products - ∑(bond energies)reactants.</em>

  • The bond formation in the products releases energy (exothermic).
  • The bond breaking in the reactants requires energy (endothermic).

The products:

  • H₂O contains 2 O-H (- 459 kJ/mol) bonds.
  • O₂ contain 1 O=O (- 494 kJ/mol) bond.

The reactants:

  • H₂O₂ contain 2 O–H (459 kJ/mol) bonds and 1 O–O (142 kJ/mol) bond.

∵ ΔHrxn = ∑(bond energies)products - ∑(bond energies)reactants.

<em>∴ ΔHrxn = [2 (2 x (O–H bond energy) + (1 x (O=O bond energy)] - 2 [(2 x (O–H bond energy) + (1 x (O–O bond energy)] </em>= [2 (2 x - 459 kJ/mol) + (1 x - 494 kJ/mol)] - 2 [(2 x 459 kJ/mol) + (1 x 142 kJ/mol)] = (- 2330 kJ) + (2120 kJ) = <em>- 210 kJ.</em>

5 0
3 years ago
¿por qué la química es considerada una ciencia natural?​
cricket20 [7]
A la química a veces se le llama "la ciencia central", porque une la física con otras ciencias naturales, como la geología y la biología. La química es el estudio de la materia y sus propiedades.




Mi mala si esto no ayuda
8 0
3 years ago
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