Answer:
5.56 A
Explanation:
From the question,
Q = it.............. Equation 1
Where Q = charges, i = current, t = time.
Make i the subject of the equation
i = Q/t.............. Equation 2
Given: Q = 200 coulombs, t = 0.6 minutes = (0.6×60) seconds
Substitite these values into equation 2
i = 200/(0.6×60)
i = 5.56 A
Hence the magnitude of the current flowing through the circuit is 5.56 A
C., used in power plants I think.
Answer:
I know 1, that is in the case of a burning of a candle.
Explanation:
Answer:
i = 5.28 A
Explanation:
The magnetic force is given by the expression
F = i l x B
the bold letters indicate vectors, let's write the modulus of that expression, where the direction between the conductor and the magnetic field is 90º, therefore the sine 90 = 1
F = i l B
i = F / l B
let's reduce the length to the SI system
l = 10 cm (1m / 100 cm) = 0.10 m
let's calculate
i = 12.9 / 0.1 3.6
i = 5.28 A