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3 years ago

Magnitude of the normal force exerted by en in the figure below. What is the

Physics

1 answer:

vekshin13 years ago

6 0

Answer:

Explanation:

Reason is that the suitcase is exerted downward and when it moves downward the equation is mgsin tita

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what is the dot product and cross product of of two vectors if the angle is between them is 90 degree?

DaniilM [7]

$\sf{\pink{\underline{\underline{\blue{GIVEN:-}}}}}$

The angle between the two vectors is 90° .

$\sf{\pink{\underline{\underline{\blue{TO\: FIND:-}}}}}$

The dot product of two vectors .
The cross product of two vectors .

$\sf{\pink{\underline{\underline{\blue{SOLUTION:-}}}}}$

⚡ Let $\rm{\vec{a}}$ and $\rm{\vec{b}}$ are the two vectors .

✍️ We have know that,

$\orange\bigstar\:\rm{\pink{\boxed{\green{\vec{a}\:.\:\vec{b}\:=\:ab\cos{\theta}\:}}}}$

Where,

θ = 90°

$\rm{\implies\:\vec{a}\:.\:\vec{b}\:=\:ab\cos{90^{\degree}}\:}$

cos 90° = 0

$\rm{\implies\:\vec{a}\:.\:\vec{b}\:=\:ab\times{0}\:}$

$\rm{\implies\:\vec{a}\:.\:\vec{b}\:=\:0\:}$

$\rm{\red{\therefore}}$ [1] The dot product of two vectors is “ 0 ” .

✍️ We have know that,

$\orange\bigstar\:\rm{\pink{\boxed{\green{\vec{a}\:\times\:\vec{b}\:=\:ab\sin{\theta}\:}}}}$

Where,

θ = 90°

$\rm{\implies\:\vec{a}\:\times\:\vec{b}\:=\:ab\sin{90^{\degree}}\:}$

sin 90° = 1

$\rm{\implies\:\vec{a}\:\times\:\vec{b}\:=\:ab\times{1}\:}$

$\rm{\implies\:\vec{a}\:\times\:\vec{b}\:=\:ab\:}$

$\rm{\red{\therefore}}$ [2] The cross product of two vectors is “ ab ” .

3 0

3 years ago

Read 2 more answers

A biologist formulates a hypothesis, performs experiments to test his hypothesis, makes careful observations, and keeps accurate

SVEN [57.7K]

The next step of the scientific method is to analyze the results and draw conclusions. After that step, if the results agree with the hypothesis, then the results should be communicated. If the results do not support the original hypothesis, then the biologist must go back to the beginning and reformulate their hypothesis based on the results of the experiment.

4 0

3 years ago

What is the period if the block’s mass is doubled? note that you do not know the value of either m or k , so do not assume any p

Oksanka [162]

The period of the block's mass is changed by a factor of √2 when the mass of the block was doubled.

The time period T of the block with mass M attached to a spring of spring constant K is given by,

T = 2π(√M/K).

Let us say that, when we increased the mass to 2M, the time periods of the block became T', the spring constant is not changed, so, we can write,

T' = 2π(√2M/K)

Putting T = 2π(√M/K) above,

T' =√2T

So, here we can see, if the mass is doubled from it's initial value. The time period of the mass will be changed by a factor of √2.