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3 years ago

what are known as the properties of substances that help describe a substance et does not change that substances?

Physics

1 answer:

Lapatulllka [165]3 years ago

5 0

Answer:

Physical properties are those that can be determined or measured without changing the composition or identity of the substance. These properties include color, odor, taste, density, melting point, boiling point, conductivity, and hardness.

Explanation:

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Which statements describe a closed circuit? Check all that apply. Bulbs will shine. Bulbs will not shine. The circuit is incompl

vaieri [72.5K]

Bulbs will shine.

The circuit is complete.

Charges flow.

4 0

3 years ago

Read 2 more answers

A flywheel of diameter 1.2 m has a constant angular acceleration of 5.0 rad/s2. the tangential acceleration of a point on its ri

vodka [1.7K]

We know that tangential acceleration is related with radius and angular acceleration according the following equation:
at = r * aa
where at is tangential acceleration (in m/s2), r is radius (in m) aa is angular acceleration (in rad/s2)
So the radius is r = d/2 = 1.2/2 = 0.6 m
Then at = 0.6 * 5 = 3 m/s2
Tangential acceleration of a point on the flywheel rim is 3 m/s2

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3 years ago

A 12.0N force with a fixed orientation does work on a

kvasek [131]

Answer:

(a) $\theta=62.31^{\circ}$

(b) $\theta=117.68^{\circ}$

Explanation:

It is given that,

Force acting on the particle, F = 12 N

Displacement of the particle, $d=(2.00i -4.00j+3.00k)\ m$

Magnitude of displacement, $d=\sqrt{2^2+4^2+3^2}= 5.38\ m$

(a) If the change in the kinetic energy of the particle is +30 J. The work done by the particle is given by :

$W=Fd\ cos\theta$

$\theta$ is the angle between force and the displacement

According to work energy theorem, the charge in kinetic energy of the particle is equal to the work done.

So,

$cos\theta=\dfrac{W}{Fd}$

$cos\theta=\dfrac{+30\ J}{12\times 5.38}$

$\theta=62.31^{\circ}$

(b) If the change in the kinetic energy of the particle is (-30) J. The work done by the particle is given by :

$cos\theta=\dfrac{W}{Fd}$

$cos\theta=\dfrac{-30\ J}{12\times 5.38}$

$\theta=117.68^{\circ}$

Hence, this is the required solution.

8 0

3 years ago

A certain electromagnetic wave traveling in seawater was observed to have an amplitude of 98.02 (V/m) at a depth of 10 m, and an

maksim [4K]

Answer:

The value is $\alpha = 0.002 Np/m$

Explanation:

From the question we are told that

The first amplitude of the wave is $E_{max}1 = 98.02 \ V/m$

The first depth is $D_1 = 10 \ m$

The second amplitude is $E_{max}2 = 81.87 \ (V/m)$

The second depth is $D_2 = 100 \ m$

Generally from the spatial wave equation we have

$v(x) = Ae^{-\alpha d}cos(\beta x + \phi_o)$

=> $\frac{v(x)}{v(x)} =\frac{ Ae^{-\alpha d}cos(\beta x + \phi_o)}{ Ae^{-\alpha d}cos(\beta x + \phi_o)}$

So considering the ratio of the equation for the two depth

$\frac{A}{A_S} = \frac{e^{-D_1 \alpha }}{e^{-D_2 \alpha }}$

=> $\frac{98.02}{81.87} = \frac{e^{-10 \alpha }}{e^{-100 \alpha }}$

=> $\alpha = \frac{0.18}{90}$

=> $\alpha = 0.002 Np/m$

4 0

4 years ago

Which statement correctly describes the relationship between the volume of a gas and its temperature, in Kelvin, assuming pressu

nekit [7.7K]

The relationship is directly proportional; as temperature increases, volume increases in the same way.

Charles's law states that at a constant pressure, the volume of fixed a mass of a gas is directly proportional to its absolute temperature or kelvin temperature.

Mathematically, this law can be written as follows;

$V = kT\\\\where;\\k \ \ is \ a \ constant \\\\T \ is \ kelvin \ temperature\\\\V \ is \ the \ volume \ of \ the \ gas$

This law explains the direct relationship between Volume of the gas and its Kelvin temperature. That is, as Temperature increases, the volume of the gas increases.

Thus, the correct statement is "The relationship is directly proportional; as temperature increases, volume increases in the same way".

Learn more here: brainly.com/question/16927784

5 0

3 years ago