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2 years ago

Since nuclear fusion in the sun creates energy from matter, why doesn't it violate the law of conservation of energy?

1 answer:

3 0

Since nuclear fusion in the sun creates energy from matter, Einstein's formula E=mc² states that matter and energy are equal.

To find the answer, we have to know more about the nuclear fusion.

<h3>What is nuclear fusion?</h3>

We are aware that the sun can achieve nuclear fusion by the fusion of hydrogen atoms.
These atoms need to get closer to one another in order to fuse.
Since both protons inside each nucleus are positively charged, they attempt to repel one another as they get closer to one another.
If this issue cannot be solved, nuclear fusion in the sun cannot occur.

Thus, we can conclude that, since nuclear fusion in the sun creates energy from matter, Einstein's formula E=mc² states that matter and energy are equal.

Learn more about nuclear fusion here:

brainly.com/question/25663405

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What is the distance between a 900 kg compact car and a 1600 kg pickup truck if the gravitational force between them is about 0.

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Answer:

The distance is 0.96m

Explanation:

Given

m1= 900kg

m2= 1600kg

Force F= 0.0001nN

G=6.67430*10^-11 Nm^2/kg^2

Required

The distance r

Step two:

the formula for the force is given as

F = Gm1m2/r2

make r subject of the formula

$r= \sqrt{\frac{Gm1m2}{F} }$

$r= \sqrt{\frac{6.67430*10^-11*900*1600}{0.0001} }\\\\r= 0.00009610992/0.0001`}\\\\r= 0.96m$

Answer:

The distance is 0.96m

Explanation:

Given

m1= 900kg

m2= 1600kg

Force F= 0.0001nN

G=6.67430*10^-11 Nm^2/kg^2

Required:

The distance r

Step two:

the formula for the force is given as

F = Gm1m2/r2

make r subject of the formula

$r= \sqrt{\frac{Gm1m2}{F} }$

$r= \sqrt{\frac{6.67430*10^-11*900*1600}{0.0001} }\\\\r= 0.00009610992/0.0001`}\\\\r= 0.96m$

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san4es73 [151]

Answer:

13.4cm

Explanation:

According to Rayleigh’s criterion the angular resolution to distinguish two objects is given by:

$\theta=1.22\frac{\lambda}{b}$

θ = 50.0*10^-7 rad

λ: wavelength of the light = 550nm

b = diameter of the objective

By doing b the subject of the formula and replacing the values of the angle and wavelength you obtain:

$b=1.22\frac{\lambda}{\theta}=1.22\frac{550*10^{-9}m}{50.0*10^{-7}rad}=0.134m=13.4cm$

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Answer:

$v = r\omega$

Explanation:

If the object is rolling without slipping, every unit of rotated angle equals to a distance perimeter rotated.

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