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1 year ago

A modest level of ethanol enters the human circulation naturally from __________, equivalent to a fraction of a drink per day.

Chemistry

1 answer:

andriy [413]1 year ago

6 0

intestinal flora

A modest level of ethanol enters the human circulation naturally from <u>intestinal flora,</u> equivalent to a fraction of a drink per day.

<h3>What is intestinal flora?</h3>

inside the intestines are bacteria and other living things.
They aid in food digestion.
Intestinal flora produces vitamins like biotin and vitamin K. Also known as intestinal microflora, microflora, and gut flora.

<h3>Are intestinal flora good?</h3>

Humans have 100 trillion viable bacteria in their intestines.
The intestinal flora is the collective name for these living bacteria, which account for 30% of the faeces bulk.
The intestinal flora contains both useful and dangerous microbes.
They are evenly distributed and the good bacteria take center stage in healthy persons.

<h3>What purpose does the gut flora serve?</h3>

Intestinal microflora primarily serves two purposes:

(1) metabolic processes that result in the absorption of nutrients and energy; and
(2) host defense against invasion by alien microbes.

The immune system's development and balance depend heavily on intestinal microorganisms.

To learn more about intestinal flora visit:

brainly.com/question/12993029

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lbvjy [14]

Answer:

i think by their salinity (the saltiness or amount of salt dissolved in a body of water)

Explanation:

Water salinity is measured by passing an electric current between the two electrodes of a salinity meter in a sample of water.

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3 years ago

Which of these are ionic compounds? Check all that apply.

SIZIF [17.4K]

I think the correct answers from the choices listed above are the first, third and the last option. Ionic compounds are compounds that dissociates into ions when in aqueous solution. From the list, NH4Cl, KF and MgO are the ionic compounds. Hope this answers the question.

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3 years ago

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Question 7 (Essay Worth 5 points)

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The periodic table of elements is divided into columns and rows. The vertical columns represent the groups while the horizontal rows represent the periods. A group of elements usually have similar physical and chemical properties. The first column of the periodic table is made up of 7 elements including SODIUM.

1. The name of the element chosen is sodium and its chemical symbol is Na.

2. Sodium is a metal and thus it has metallic properties.

3. Sodium belongs to group one elements whose family name is ALKALI METALS.

4. The neutral atom of sodium is made up of 11 protons, 11 electrons and 12 neutrons.

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3 years ago

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Classical name for chromium(III) phosphate

prohojiy [21]

If by classical you mean formula name it is CrPO4<span>.</span>

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3 years ago

In the laboratory a student combines 26.2 mL of a 0.234 M chromium(III) acetate solution with 10.7 mL of a 0.461 M chromium(III)

Natalka [10]

<u>Answer:</u> The molarity of $Cr^{3+}$ ions in the solution is 0.299 M

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$ .....(1)

<u>For chromium (III) acetate:</u>

Molarity of chromium (III) acetate solution = 0.234 M

Volume of solution = 26.2 mL

Putting values in equation 1, we get:

$0.234=\frac{\text{Moles of chromium (III) acetate}\times 1000}{26.2}\\\\\text{Moles of chromium (III) acetate}=\frac{0.234\times 26.2}{1000}=0.00613mol$

1 mole of chromium (III) acetate $(Cr(CH_3COO)_3)$ produces 1 mole of chromium $(Cr^{3+})$ ions and 3 moles of acetate $(CH_3COO^-)$ ions

Moles of $Cr^{3+}\text{ ions}=(1\times 0.00613)=0.00613moles$

<u>For chromium (III) nitrate:</u>

Molarity of chromium (III) nitrate solution = 0.461 M

Volume of solution = 10.7 mL

Putting values in equation 1, we get:

$0.461=\frac{\text{Moles of chromium (III) nitrate}\times 1000}{10.7}\\\\\text{Moles of chromium (III) nitrate}=\frac{0.461\times 10.7}{1000}=0.00493mol$

1 mole of chromium (III) nitrate $(Cr(NO_3)_3)$ produces 1 mole of chromium $(Cr^{3+})$ ions and 3 moles of nitrate $(NO_3^-)$ ions

Moles of $Cr^{3+}\text{ ions}=(1\times 0.00493)=0.00493moles$

<u>For chromium cation:</u>

Total moles of chromium cations = [0.00613 + 0.00493] = 0.01106 moles

Total volume of solution = [26.2 + 10.7] = 36.9 mL

Putting values in equation 1, we get:

$\text{Molarity of }Cr^{3+}\text{ cations}=\frac{0.01106\times 1000}{36.9}\\\\\text{Molarity of }Cr^{3+}\text{ cations}=0.299M/tex]Hence, the molarity of [tex]Cr^{3+}$ ions in the solution is 0.299 M

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3 years ago