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rosijanka [135]
3 years ago
6

What happens to volume if pressure and temperature are doubled?

Physics
1 answer:
Ahat [919]3 years ago
8 0
Pv=nrt if the temp. and pressure double the equation is sound and volume remain 
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The net external force on a golf cart is 411 N north of tha cart has a total mass of 281 kg what is tha cart acceleration
Alisiya [41]

1.46m/s²

Explanation:

Given parameters:

Mass of cart = 281kg

Net external force = 411N

Unknown:

Acceleration of the cart = ?

Solution:

According to newton's second law " the net force on a car is the product of its mass and acceleration";

            Force = mass x acceleration

Since acceleration of the cart is unknown;

     Acceleration = \frac{force}{mass} = \frac{411}{281}

  Acceleration = 1.46m/s²

learn more:

Newton's laws brainly.com/question/11411375

#learnwithBrainly

8 0
3 years ago
10.   Cumulus and stratus clouds belong to which cloud group? <br><br>     
EastWind [94]
Cumulus belongs to vertical clouds and status to low
5 0
4 years ago
The magnitude of each force is 208 N the force on the right is applied at an angle 36° and the mass of the block is 17 kg the co
djyliett [7]

Answer:

<em>11.06m/s²</em>

Explanation:

According to Newtons second law of motion

\sm F_x = ma_x\\F_m - F_f = ma_x\\mgsin \theta - \mu R mgcos \theta = ma_x\\

Given

Mass m = 17kg

Fm = 208N

theta = 36 degrees

g = 9.8m/s²

a is the acceleration

Substitute

208 - 0.148(17)(9.8)cos 36 = 17a

208 - 24.6568cos36 = 17a

208 - 19.9478 = 17a

188.05 = 17a

a = 188.05/17

a = 11.06m/s²

<em>Hence the  the magnitude of the resulting acceleration is 11.06m/s²</em>

6 0
3 years ago
What is the difference between a data table and a graph?
alexandr402 [8]

At the same time, however, you get less detail or less precision in a chart or graph than you do in the table. Imagine the difference between a table of sales figures for a ten-year period and a line graph for that same data. You get a better sense of the overall trend in the graph but not the precise dollar amount.

3 0
4 years ago
Read 2 more answers
A ball is thrown horizontally from the top of a building 22.3 m high. The ball strikes the ground at a point 127 m from the base
DochEvi [55]

Answer:

t = 2.13 s

Explanation:

given,

height of the building = 22.3 m

horizontal distance = 127 m

acceleration due to gravity = 9.8 m/s²

time for which ball is in motion = ?

using equation of motion

s = u t + \dfrac{1}{2}gt^2

initial velocity is zero

s = \dfrac{1}{2}gt^2

t = \sqrt{\dfrac{2s}{g}}

t = \sqrt{\dfrac{2\times 22.3}{9.8}}

       t = √4.551

        t = 2.13 s

8 0
3 years ago
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