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2 years ago

WILL GIVE BRAINLIEST

Physics

1 answer:

Vilka [71]2 years ago

6 0

Answer:

4.44m/s

Explanation:

Given parameters:

Number of laps = 4

Length of track = 400m

Time taken = 6min

Unknown:

Average speed = ?

Solution:

The average speed is the total distance covered divided by the time taken.

It is mathematically expressed as;

Average speed = $\frac{total distance}{time taken}$

Total distance = number of laps x length of track = 4 x 400 = 1600m

Now convert the time to seconds;

60s = 1 min

6 minutes will be 6 x 60 = 360s

So;

Average speed = $\frac{1600}{360}$ = 4.44m/s

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In a natural gas power plant, natural gas is burned to heat steam, which turns a turbine. What energy conversion is happening in

Irina18 [472]

<h2>Hello!</h2>

The answer is A. Chemical energy to heat energy to kinetic energy to electrical energy.

Let's check the energy conversion given in the statement:

Chemical energy: Chemical energy is usually obtained from a natural resource combustion. For this particular case is the result of natural gas combustion.

Heat energy: Heat energy comes from chemical reactions such as natural gas combustions.

Kinetic energy: Kinetic energy is obtained by turbines transforming the pressurized steam on mechanical movement. Turbines are formed by a turbine that absorbs the heat energy to do mechanical work and transmit it to an output rotating shaft.

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2 years ago

Read 2 more answers

2) [25 pts] The bob of mass m=5 kg shown in the figure is being held by a force F. If the angle is 0⃗

Colt1911 [192]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The tension is $T = 48.255 \ N$

The time taken is $t = 0.226 \ s$

The position for maximum velocity is

S = 0

The maximum velocity is $V_{max} =0.384 \ m/s$

Explanation:

The free body for this question is shown on the second uploaded image

From the question we are told that

The mass of the bob is $m_b = 5 \ kg$

The angle is $\theta = 10^o$

The length of the string is $L = 0.5 \ m$

The tension on the string is mathematically represented as

$T = mg cos \theta$

substituting values

$T = 5 * 9.8 cos(10)$

$T = 48.255 \ N$

The motion of the bob is mathematically represented as

$S = A sin (w t + \frac{\pi }{2} )$

=> $S = A sin (wt)$

Where $w$ is the angular speed

and $\frac{\pi}{2}$ is the phase change

At initial position S = 0

So $wt = cos^{-1} (0)$

$wt = 1$

Generally $w$ can be mathematically represented as

$w = \frac{2 \pi }{T}$

Where T is the period of oscillation which i mathematically represented as

$T = 2 \pi \sqrt{\frac{L}{g} }$

$t = \frac{1}{w}$

$t = \frac{T}{2 \pi}$

$t = \sqrt{\frac{L}{g} }$

substituting values

$t = \sqrt{\frac{0.5}{9.8} }$

$t = 0.226 \ s$

Looking at the equation

$wt = 1$

We see that maximum velocity of the bob will be at S = 0

i. e $w = \frac{1}{t}$

The maximum velocity is mathematically represented as

$V_{max} = w A$

Where A is the amplitude which is mathematically represented as

$A = L sin \theta$

$V_{max} = \frac{2 \pi }{T } L sin \theta$

$V_{max} = \frac{2 \pi }{2 \pi } \sqrt{\frac{g}{L} } L sin \theta$ Recall $T = 2 \pi \sqrt{\frac{L}{g} }$

$V_{max} = \sqrt{gL} sin \theta$

substituting values

$V_{max} = \sqrt{9.8 * 0.5 } sin (10)$

$V_{max} =0.384 \ m/s$

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2 years ago

A soccer ball is kicked from the ground with an initial speed v at an upward angle θ. A player a distance d away in the directio

LuckyWell [14K]

Answer:

U = √Rg/sin2θ

Explanation:

Using the formula for "range" in projectile motion to derive the average speed before the ball hits the ground.

Range is the distance covered by the body in the horizontal direction from the point of launch to the point of landing.

According to the range formula,

R = U²sin2θ/g

Cross multiplying we have;

Rg = U²sin2θ

Dividing both sides by sin2θ, we have;

U² = Rg/sin2θ

Taking the square root of both sides we have;

√U² = √Rg/sin2θ

U = √Rg/sin2θ

Therefore, his average speed if he is to meet the ball just before it hits the ground is √Rg/sin2θ

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3 years ago

a box is at rest on a ground. An unbalance force acts on the box causes it to start. The box moves 10 meters in 2 seconds and th

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The box stopped moving because there was a negative acceleration in the x direction caused by friction.
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