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andrey2020 [161]
2 years ago
9

An electrical layout is a drawing that indicates how the ________ of a circuit will be connected to one another and where the wi

res will be run.
Engineering
1 answer:
Natali5045456 [20]2 years ago
5 0

Answer:

Component parts

Explanation:

An electrical layout is a drawing that indicates how the component parts of a circuit will be connected to one another and where the wires will be run.

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Where does Mr. Teller work? What do they do there?
natulia [17]

Most business owners begin his business in order to increase profit and to expand.

<h3>What are Business Practices?</h3>

This refers to the various ways in which a business owner decides to organize his business and the policies which guides it.

With this in mind, we can see that Mr X believes that it is a good business practice to <em>prioritize the work</em> that seems the most difficult and the most likely to kill their projects but this is not a good business practice because it can put the entire business in jeopardy.

Please note that your question is incomplete so I gave you a general overview so that you could get a better understanding of the concept.

Read more about business practises here:
brainly.com/question/1343903

7 0
2 years ago
(c) As Engineering and Computing students, you must be familiar, with the respective professional bodies, as well as, Rules of P
guajiro [1.7K]

The professional ethics for computer engineers are:

  • They will Contribute to society and to human well-being.
  • They will  Avoid harm.
  • Be honest and trustworthy.
  • They will be fair and take action that do to discriminate others.

<h3>What are the Characteristics of Code of Ethics?</h3>

The code of ethics are known to be a kind of a universal moral values, that is one that state that what a person expect of any given employee such as been trustworthy, respectful, responsible, and others.

Note that Rules of Practice, Professional Obligations and Codes of Ethics. are known to be put in place to avoid issues that may lead to conflict.

Therefore, i believe that  As Engineering and Computing students, the respective professional bodies, Rules of Practice, Professional Obligations and Codes of Ethics are good and acts as a check and balance to us.

Therefore, The professional ethics for computer engineers are:

  • They will Contribute to society and to human well-being.
  • They will  Avoid harm.
  • Be honest and trustworthy.
  • They will be fair and take action that do to discriminate others.

Learn more about Engineering rules from

brainly.com/question/17169621

#SPJ1

4 0
1 year ago
A non-inductive load takes a current of 15A at 125V. An inductor is then connected in series in order that the same current shal
Norma-Jean [14]

Answer:

The inductance of the inductor is 0.051H

Explanation:

From Ohm's law;

  V = IR .................. 1

The inductor has its internal resistance referred to as the inductive reactance, X_{L}, which is the resistance to the flow of current through the inductor.

From equation 1;

V = IX_{L}

X_{L} = \frac{V}{I} ................ 2

Given that; V = 240V, f = 50Hz, \pi = \frac{22}{7}, I = 15A, so that;

From equation 2,

X_{L}= \frac{240}{15}

    = 16Ω

To determine the inductance of the inductor,

X_{L} = 2\pifL

L = \frac{X_{L} }{2 \pi f}

  = \frac{16}{2*\frac{22}{7}*50 }

 = 0.05091

The inductance of the inductor is 0.051H.

4 0
3 years ago
You are an engineer in an electric-generation station. You know that the flames in the boiler reach a temperature of 1200 K and
andre [41]

Answer:

...wat

Explanation:

6 0
3 years ago
Consider a cylindrical nickel wire 2.1 mm in diameter and 3.2 × 104 mm long. Calculate its elongation when a load of 280 N is ap
pshichka [43]

Answer:

Total elongation will be 0.012 m

Explanation:

We have given diameter of the cylinder = 2.1 mm

Length of wire L=3.2\times 10^4mm

So radius r=\frac{d}{2}=\frac{2.1}{2}=1.05mm=1.05\times 10^{-3}m

Load F = 280 N

Elastic modulus = 207 Gpa

Area of cross section A=\pi r^2=3.14\times (1.05\times 10^{-3})^2=3.461\times 10^{-6}m^2

We know that elongation in wire is given by \delta =\frac{FL}{AE}, here F is load, L is length, A is area and E is elastic modulus

So \delta =\frac{FL}{AE}=\frac{280\times 32}{3.461\times 10^{-6}\times 207\times 10^9}=0.012m

4 0
3 years ago
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