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lara [203]
4 years ago
13

Two parakeets sit on a swing with their combined center of mass 10.0 cm below the pivot. At what frequency do they swing?

Physics
1 answer:
Oksanka [162]4 years ago
7 0

Answer:

1.58 Hz

Explanation:

The frequency of the simple pendulum is given by

f = 1/T

 = 1/2π√g/l  

In this problem, I = 10.0 cm = 0.1 m  

f = 1/2π√9.8/0.1

=  1.58 Hz

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Vector ~A has a negative x-component 3.07 units in length and a positive y-component 3.17 units in length. When a vector ~B = b1
luda_lava [24]

Answer:

a. 3.07 b. 1.26

Explanation:

Given that A = -3.07i + 3.17j and B = b1i + b1j and C = A + B = 0i + 4.43j

Since A + B = -3.07i + 3.17j + b1i + b2j

= (-3.07 + b1)i + (3.17 + b2)j

So,(-3.07 + b1)i + (3.17 + b2)j = 0i + 4.43j

Comparing components,

-3.07 + b1 = 0 (1) and 3.17 + b2 = 4.43 (2)

a. From (1), b1 = 3.07

b. From(2) b2 = 4.43 - 3.17 = 1.26

4 0
3 years ago
Ammonia gas occupies a volume of 0.450 L at a pressure of 96 kPa. What
Sauron [17]

Answer:

0.426 L

Explanation:

Boyles law is expressed as p1v1=p2v2 where

P1 is first pressure, v1 is first volume

P2 is second pressure, v2 is second volume.

Given information

P1=96 kPa, v1=0.45 l

P2=101.3 kpa

Unknown is v2

Making v2 the subject from Boyle's law

v2=\frac {p1v1}{p2}

Substituting the given values then

v2=\frac {96*0.45}{101.3}=0.4264560710760l\approx 0.426 l

Therefore, the volume is approximately 0.426 L

6 0
3 years ago
Using this formula a = F/m What acceleration results from exerting a 125N force on a 0.65kg
Softa [21]

Answer:

Acceleration = 192.3 m/s² (Approx.)

Explanation:

Given:

Force = 125 N

Mass of ball = 0.65 kg

Find:

Acceleration

Computation:

We know that;

Acceleration = Force / Mas

So,

Acceleration = 125 / 0.65

Acceleration = 192.3 m/s² (Approx.)

5 0
3 years ago
A 1000-kg car is moving at 30 m/s around a horizontal unbanked curve whose diameter is 0.20 km. What is the magnitude of the fri
omeli [17]

Answer:

4500 N

Explanation:

When a body is moving in a circular motion it will feel an acceleration directed towards the center of the circle, this acceleration is:

a = v^2/r

where v is the velocity of the body and r is the radius of the circumference:

Therefore, a body with mass m, will feel a force f:

f = m v^2/r

Therefore we need another force to keep the body(car) from sliding, this will be given by friction, remember that friction force is given a the normal times a constant of friction mu, that is:

fs = μN = μmg

The car will not slide if     f = fs,   i.e.

fs = μmg =  m v^2/r

That is, the magnitude of the friction force must be (at least) equal to the force due to the centripetal acceleration

fs = (1000 kg)  * (30m/s)^2 / (200 m) = 4500 N

7 0
3 years ago
Read 2 more answers
An astronaut is moving in space when a big explosion occurs about 50 metres BEHIND him. How will the astronaut come to know abou
kakasveta [241]
The matter from the explosion can reach him, hitting him. He should be able to feel that.
6 0
3 years ago
Read 2 more answers
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