If the ball does not loose any energy to friction and cannot bounce, where will it eventually stop?
1 answer:
You might be interested in
To solve this problem it is necessary to apply the rules and concepts related to logarithmic operations.
From the definition of logarithm we know that,
In this way for the given example we have that a logarithm with base 10 expressed in the problem can be represented as,
We can express this also as,
By properties of the logarithms we know that the logarithm of a power of a number is equal to the product between the exponent of the power and the logarithm of the number.
So this can be expressed as
Since the definition of the base logarithm 10 of 10 is equal to 1 then
The value of the given logarithm is equal to 6
Answer:
A)
B)
C)
Explanation:
For this case we want to create a function like this:
Where Z represent the degrees for the Z scale C the Celsius grades and tha valus a and b parameters for the model.
The boiling point of nitrogen is -195,8 °C
The melting point of iron is 1538 °C
We know the following equivalences:
-195.8 °C = 0 °Z
1538 °C = 1000 °Z
Let's say that one point its (1538C, 1000 Z) and other one is (-195.8 C, 0Z)
So then we can calculate the slope for the linear model like this:
And now for the slope we can use one point let's use for example (-195.8C, 0Z), and we have this:
And if we solve for b we got:
So then our lineal model would be:
Part A
The boiling point of water is 100C so we just need to replace in the model and see what we got:
Part B
For this case we have Z =100 and we want to solve for C, so we can do this:
Part C
For this case we know that
And we can use the result from part B to solve for K like this: