The work done to stop the car is -208.33 kJ
From work-kinetic energy principles, the change in kinetic energy of the car ,ΔK equals the work done to stop the car, W.
W = ΔK = 1/2m(v'² - v²) where
- m = mass of car = 1500 kg,
- v = initial velocity of car = 60 km/h = 60 × 1000 m/3600 s = 16.67 m/s and
- v' = final velocity of car = 0 m/s (since the car stops).
<h3 /><h3>Calculating the work done</h3>
Substituting the values of the variables into the equation, we have
W = 1/2m(v'² - v²)
W = 1/2 × 1500 kg(v(0 m/s)² - (16.67 m/s)²)
W = 750 kg(0 (m/s)² - 277.78 (m/s)²)
W = 750 kg(- 277.78 (m/s)²)
W = -208333.33 J
W = -208.33333 kJ
W ≅ -208.33 kJ
So, the work done to stop the car is -208.33 kJ
Learn more about work done here:
brainly.com/question/9821607
It is medium loud because very loud is called forte.
mezzo means medium. forte means loud. mezzo forte means medium loud.
answer: d) medium loud
I believe it is Acoustics, the real name for it would be like Reverberation. But go with Acoustics. :)
Answer:
The answer to your question is 636.6 ft
Explanation:
Data
base = 425 ft
angle = 39°
See the picture below
1.- Divide the triangle to get two right triangles.
Now the superior angle will measure 19.5° and the opposite side will measure 212.5 ft
2.- Use the trigonometric function sine to find the hypotenuse
sin 19.5 = 212.5/hyp
solve for hyp
hyp = 212.5 / sin 19.5
Result
hyp = 212.5/ 0.333
hyp = 636.6 ft
