Explanation:
a) The height of the ball h with respect to the reference line is

so its initial gravitational potential energy
is



b) To find the speed of the ball at the reference point, let's use the conservation law of energy:

We know that the initial kinetic energy
as well as its final gravitational potential energy
are zero so we can write the conservation law as

Note that the mass gets cancelled out and then we solve for the velocity v as



Answer:
Average speed=1.5 m/s
Frequency of pendulum=93.75Hz
Explanation:
We are given
Frequency, 
Average wavelength =
Speed of pendulum, 
Wavelength, 
We have to find the average speed and frequency of pendulum.
We know that
Speed,
Using the formula
Average speed,
Hence, the average speed =1.5m/s
Frequency, 
Using the formula


Hence, the frequency of a pendulum=93.75Hz
They size of the wave and the time of a certain wave.
Answer:
19.53 cm
Explanation:
The computation of the height is as follows:
Here we applied the conservation of the energy formula
As we know that
P.E of the block = P.E of the spring
m g h = ( 1 ÷ 2) k x^2
where
m = 0.15
g = 9.81
k = 420
x = 0.037
So now put the values to the above formula
(0.15) (9.81) (h) = 1 ÷2 × 420 × (0.037)^2
1.4715 (h) = 0.28749
h = 0.19537 m
= 19.53 cm
Answer:
Distance, d = 0.1 m
It is given that,
Initial velocity of meson,
Finally, the meson is coming to rest v = 0
Acceleration of the meson, (opposite to initial velocity)
Using third equation of motion as :
s is the distance the meson travelled before coming to rest.
So,
s = 0.1 m
The meson will cover the distance of 0.1 m before coming to rest. Hence, this is the required solution.