Which of the following is a chemical change

Chemistry

2 answers:

Inessa [10]2 years ago

6 0

D because it’s changing the Material

gayaneshka [121]2 years ago

4 0

The answer is D :) good luck

You might be interested in

The reaction between nitric oxide and oxygen is described by the following chemical equation: Suppose a two-step mechanism is pr

muminat

Answer:

2NO(g) + O2(g) ---> 2NO2(g)

Explanation:

The mechanism for this reaction involves two elementary reactions in which both are bimolecular as shown below;

NO(g) +O2(g) ----> NO2(g) + O(g)

NO(g) + O(g) ----> NO2(g)

Hence overall balanced reaction equation;

2NO(g) + O2(g) ---> 2NO2(g)

7 0

3 years ago

In order to prepare very dilute solutions, a lab technician chooses to perform a series of dilutions instead of measuring a very

laiz [17]

Answerit is a

Explanation:

8 0

2 years ago

Calculate the entropy change for the reaction: Fe2O3(s) +3C(s) -> 2Fe(s) + 3CO(g)Entropy data:Fe2O3(s): 90 J/K molC(s): 5.7 J

Annette [7]

Explanation:

We are given: entropy of Fe2O3 = 90J/K.mol

: entropy of C = 5.7J/K.mol

: entropy of Fe = 27.2J/K.mol

: entropy of CO = 198J/K.mol

$\begin{gathered} \Delta S\text{ = S}_{products}-S_{reactants} \\ \\ \text{ = \lparen3}\times198+2\times27.2)-(3\times5.7+90) \\ \\ \text{ = 541.3J/K.mol} \end{gathered}$

Answer:

The correct answer is C.

5 0

5 months ago

A 0.4322 g sample of a potassium hydroxide – lithium hydroxide mixture requires 27.10 mL of 0.3565 M HCl for its titration to th

Yuki888 [10]

The mass percent lithium hydroxide in the mixture with potassium hydroxide, calculated from the equivalence point in the titration of HCl with the mixture, is 19.0%.

The mass percent of lithium hydroxide can be calculated with the following equation:

$\% = \frac{m_{LiOH}}{m_{t}} \times 100$ (1)

Where:

$m_{t} = m_{KOH} + m_{LiOH} = 0.4322 g$ (2)

We need to find the mass of LiOH.

From the titration, we can find the number of moles of the mixture since the number of moles of the acid is equal to the number of moles of the bases at the equivalence point.

$\eta_{HCl} = \eta_{LiOH} + \eta_{KOH}$