Atomic <span>mass He = 4.002 u.m.a
4.002 g --------------- 6.02x10</span>²³ atoms
50 g ------------------ ? atoms
50 x ( 6.02x10²³) / 4.002
= 3.01x10²⁵ / 4.002
= 7.52x10²⁴ atoms of He
Answer:
<h3>The answer is 41.05 %</h3>
Explanation:
The percentage error of a certain measurement can be found by using the formula
From the question
actual density = 0.95 g/mL
error = 0.95 - 0.56 = 0.39
So we have
We have the final answer as
<h3>41.05 %</h3>
Hope this helps you
Answer:
Explanation:
We have to make 100 mL 0f .405M HCl from 3 M solution of HCl .
volume of 3M to be taken required . Let this volume be V litre .
V litre of 3M will contain 3 V moles of HCl .
moles contained by 100 mL of ,405 HCl = .405 x .1 = .0405 moles .
So 3V = .0405
V = .0405 / 3 litre
= .0405 x 1000 / 4 mL
= 10.125 mL
So we have to take 10.125 mL of 3M HCl and add water to them to make its volume 100 mL .
Answer: The partial pressure of oxygen is 187 torr.
Explanation:
According to Raoult's law, the partial pressure of a component at a given temperature is equal to the mole fraction of that component multiplied by the total pressure.
where, x = mole fraction
= total pressure
,
,
Thus the partial pressure of oxygen is 187 torr.
Answer:
V₂ = 3227.46 L
Explanation:
Given data:
Initial volume of gas = 1000 L
Initial temperature = 50°C (50 +273 = 323 K)
Initial pressure = 101.3 KPa
Final pressure = 27.5 KPa
Final temperature = 10°C (10 +273 = 283 K)
Final volume = ?
Solution:
According to general gas equation:
P₁V₁/T₁ = P₂V₂/T₂
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 101.3 KPa × 1000 L × 283 K / 323 K × 27.5 KPa
V₂ = 28667900 KPa .L. K /
8882.5 K.KPa
V₂ = 3227.46 L
