How many grams of water will be produced when 1.6 moles of ethanol (CH3CH2OH) are burned completely? Enter a number only (no uni
1 answer:
Answer:
86
Explanation:
The reaction that takes place is:
- C₂H₅OH + 3O₂ → 2CO₂ + 3H₂O
First we <u>convert moles of ethanol to moles of water</u>:
- 1.6 mol ethanol *
= 4.8 mol H₂O
Then we <u>convert moles of water to grams of water</u>, using its molar mass:
- 4.8 mol H₂O * 18 g/mol = 86.4 g
So 84.6 grams of water will be produced.
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Answer :
The order of reaction is, 0 (zero order reaction).
The value of rate constant is,
Explanation :
Half life : It is defined as the time in which the concentration of a reactant is reduced to half of its original value.
The general expression of half-life for nth order is:
or,
or,
.............(1)
where,
= half-life of the reaction
n = order of reaction
[A] = concentration
As we are given:
Initial concentration of A = 0.229 M
Final concentration of A = 0.639 M
Initial half-life of the reaction = 29.5 s
Final half-life of the reaction = 82.3 s
Now put all the given values in the above formula 1, we get:
Thus, the order of reaction is, 0 (zero order reaction).
Now we have to determine the rate constant.
To calculate the rate constant for zero order the expression will be:
When,
= 29.5 s
= 0.229 M
Thus, the value of rate constant is,