Explanation:
The equation of the reaction is given as;
Be + 2HCl → BeCl2 + H2
What is the mass of beryllium required to produce 25.0g of beryllium chloride?
1 mol of Be produces 1 mol of BeCl2
Converting to mass;
Mass = Molar mass * Number of moles
9.01g of Be produces 79.92g of BeCl2
xg of Be produces 25g of BeCl2
Solving for x;
x = 25 * 9.01 / 79.92
x = 2.82 g
What is the mass of hydrochloric acid required to produce 25.0g of beryllium chloride? g
Converting 25.0g of beryllium chloride to moles;
Number of moles = Mass / Molar mass
Number of moles = 25 / 79.92 = 0.3128 mol
2 mol of HCl produces 1 mol of BeCl2
x mol of HCl would produce 0.3128 mol of BeCl2
solving for x;
x = 0.3128 * 2 = 0.6256 mol
Converting to mass;
Mass = 0.6256 * 36.5 = 22.83 g
What is the mass of hydrogen gas produced when 25.0g of beryllium chloride is also produced? g
25g of BeCl2 = 0.3128 mol of BeCl2
From the equation;
1 mol of H2 is produced alongside 1 mol of BeCl2
This means;
0.3128 mol of H2 would also be produced alongside 0.3128 mol of BeCl2
Mass = Number of moles * Molar mass
Mass = 0.3128mol * 2.0159 g/mol = 0.6306 g
= 4.8 mol H₂O