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Anon25 [30]
1 year ago
11

When pcl5 solidifies it forms pcl4 cations and pcl6–anions. according to valence bond theory, what hybrid orbitals are used by p

hosphorus in the pcl4 cations?
Chemistry
1 answer:
SSSSS [86.1K]1 year ago
5 0

When pcl5 solidifies it forms pcl4 cations and pcl6–anions. according to valence bond theory, hybrid orbitals that  are used by phosphorus in the pcl4 cations are one orbital of s and three orbital of p as it is sp³hydridised.

<h3>What is sp³ hybridization?</h3>

Hybridization is a process or system which specifies the shape and geometry of any element or molecule with bond angles too.

The pcl4 cation is sp³ hybridized because of the phosphorus behave as a central atom here and the 4 chloride molecules are attached with the p- orbitals to the phosphorus molecule.

Therefore, pcl4 cation  is sp³ hybridized.

Learn more about sp³ hybridization, here :

brainly.com/question/13062274

#SPJ4

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In a molecule of calcium sulfide, calcium has two valence electron bonds, and a sulfur atom has six valence electrons. How many
mote1985 [20]

There are none

<h3>Further explanation</h3>

Given

a molecule of calcium sulfide

two valence electron of Calcium(Ca)

six valence electrons of Sulfur(S)

Required

number of lone pairs of electrons

Solution

Lewis structure shows the form of bonds that occur in the valence electrons of an element or compound

Valence electrons are electrons used in a chemical bond

To achieve stability, the element S needs 2 more electrons which are obtained from 2 electrons from the Ca element,

A lone pair electron means refers to an unshared pair of electrons(not bonding to the other atoms)

This condition usually occurs in covalent bonds

As we know, the bond between Ca, which is a group 2 (metal) with Sulfur in group 16, is an ionic bond because it occurs between metal and non-metal ions, so there is no sharing of electrons, but there is a release of electrons from Ca ions to S ions to form an octet. , so all the valence electrons in S are paired

7 0
3 years ago
Consider the following reaction: 3Fe(s) + 4H₂O(g) ➞ Fe₃O₄(s) + 4H₂(g). To answer the following question: "How many moles of hot
Elodia [21]

Answer: 2

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}

\text{Moles of} Fe_3O_4=\frac{275g}{233.5g/mol}=1.18moles

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According to stoichiometry :

1 mole of Fe_3O_4 are produced by = 4 moles of H_2O

Thus 1.18 moles of Fe_3O_4 will be produced by=\frac{4}{1}\times 1.18=4.72moles  of H_2O

Mass of H_2O=moles\times {\text {Molar mass}}=4.72moles\times 18g/mol=85.0g

Thus 85.0  g of H_2O will be required and 2 steps are required to get the answer.

6 0
3 years ago
Iodine-138 decays by beta decay. What element does it produce?
iVinArrow [24]

{xe}^{138}

Explanation:

the bottom number would be 54. This is because you add one to 53 to make it 54 and you add 0 to 138.

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2 years ago
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attashe74 [19]

You are testing which fertilizer makes the radishes grow the fastest.

factors you should control: sunlight exposure, water amount, fertilizer amount.

Measure: check the rows of radishes to see how much each row has grown in comparison to the others. Whichever row with the healthiest radishes has the best fertilizer.

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I hope this helps sorry if it doesn’t

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