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Lina20 [59]
1 year ago
8

An atom of 65as has a mass of 64. 949563 amu. mass of1h atom = 1. 007825 amu mass of a neutron = 1. 008665 amu. calculate the ma

ss defect (deficit) in amu/atom.
Chemistry
1 answer:
sukhopar [10]1 year ago
4 0

The mass defect of an atom is 10.672592 amu/atom.

The mass defect is the discrepancy between the nucleus of an atom's anticipated mass and its actual mass. This discrepancy is due to the binding energy of a system, which might manifest as excess mass.

A key characteristic of a nucleus is the nuclear mass defect, which has a set value equal to a specific amount of binding energy for that nucleus.

The binding energy (BE) of a nucleus is the mass defect multiplied by the square of the speed of light or the energy released during the nucleus' formation.

Mass of the atom = 64.949563 amu

Mass of the proton = 1.007825 amu

Mass of the neutron = 1.008665 amu

Arsenic has 33 protons and 42 neutrons.

Mass defect = Mp + Mn - MA

                    = 33 × 1.007825 + 42 ×  1.008665 - 64.949563

                    = 33.258225 + 42.36393 - 64.949563

                    = 10.672592 amu/atom

Therefore, the mass defect of atom is 10.672592 amu/atom.

Learn more about mass defect here:

brainly.com/question/11410788

#SPJ4

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Answer:

\displaystyle \frac{dh}{dt} = \frac{1}{10 \pi}

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We have \displaystyle \frac{dV}{dt} = \frac{10 \ cm^3}{sec} and we want to find \displaystyle \frac{dh}{dt} \Biggr | _{h\ =\ 6}= \ ? when the height is 2 cm.

We can see in our equation for the volume of a cone that we have three variables: V, r, and h.

Since we only have dV/dt and dh/dt, we can rewrite the equation in terms of h only.

We are given that the height of the cone is 1/5 the radius at any given time, 1/5r, so we can write this as r = 5h.

Plug this value for r into the volume formula:

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Differentiate this equation with respect to time t.

  • \displaystyle \frac{dV}{dt}  =\frac{25}{3} \pi \ 3h^2 \ \frac{dh}{dt}
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Plug known values into the equation and solve for dh/dt.

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